Math

QuestionCheck if (fg)(x)(f \circ g)(x) equals (gf)(x)(g \circ f)(x) for f(x)=7x2f(x)=7x-2 and g(x)=2x7g(x)=2x-7. Simplify (fg)(x)=((f \circ g)(x)=\square( )).

Studdy Solution

STEP 1

Assumptions1. The function f(x)f(x) is defined as 7x7x - . The function g(x)g(x) is defined as x7x -7
3. We need to check if the composition of functions (fg)(x)(f \circ g)(x) is equivalent to (gf)(x)(g \circ f)(x)

STEP 2

First, let's find (fg)(x)(f \circ g)(x), which means we apply the function g(x)g(x) first and then apply the function f(x)f(x) to the result.(fg)(x)=f(g(x)) (f \circ g)(x) = f(g(x))

STEP 3

Now, substitute g(x)g(x) into f(x)f(x).
f(g(x))=7g(x)2 f(g(x)) =7g(x) -2

STEP 4

Substitute the definition of g(x)g(x) into the equation.
f(g(x))=7(2x7)2 f(g(x)) =7(2x -7) -2

STEP 5

implify the equation.
f(g(x))=14x492 f(g(x)) =14x -49 -2

STEP 6

Further simplify the equation.
f(g(x))=14x51 f(g(x)) =14x -51

STEP 7

Now, let's find (gf)(x)(g \circ f)(x), which means we apply the function f(x)f(x) first and then apply the function g(x)g(x) to the result.
(gf)(x)=g(f(x)) (g \circ f)(x) = g(f(x))

STEP 8

Now, substitute f(x)f(x) into g(x)g(x).
g(f(x))=2f(x)7 g(f(x)) =2f(x) -7

STEP 9

Substitute the definition of f(x)f(x) into the equation.
g(f(x))=2(7x2)7 g(f(x)) =2(7x -2) -7

STEP 10

implify the equation.
g(f(x))=14x47 g(f(x)) =14x -4 -7

STEP 11

Further simplify the equation.
g(f(x))=14x11 g(f(x)) =14x -11

STEP 12

Now that we have both (fg)(x)(f \circ g)(x) and (gf)(x)(g \circ f)(x), we can compare them to check if they are equivalent.
f(g(x))=14x51 f(g(x)) =14x -51 g(f(x))=14x11 g(f(x)) =14x -11 From the above, we can see that (fg)(x)(f \circ g)(x) is not equivalent to (gf)(x)(g \circ f)(x).

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