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Math

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PROBLEM

For number 10 and 11 graph the function and identify the domain and range.
10) f(x)=x3f(x)=\sqrt{x-3}
11) g(x)=x+4g(x)=\sqrt{x+4}
For number 12-13 solve the equation and check your answer.
12) 35x+63=183 \sqrt[3]{5 x+6}=18

STEP 1

Assumptions for Problem 10 and 11
1. We are given two functions: f(x)=x3 f(x) = \sqrt{x-3} and g(x)=x+4 g(x) = \sqrt{x+4} .
2. We need to graph each function.
3. We need to identify the domain and range of each function.

STEP 2

For f(x)=x3 f(x) = \sqrt{x-3} , determine the domain.
The expression under the square root, x3 x-3 , must be non-negative for the function to be defined.
x30 x - 3 \geq 0

STEP 3

Solve the inequality for the domain of f(x) f(x) .
x3 x \geq 3 Thus, the domain of f(x) f(x) is [3,) [3, \infty) .

STEP 4

Identify the range of f(x)=x3 f(x) = \sqrt{x-3} .
Since the square root function produces non-negative outputs, the range is:
[0,) [0, \infty)

STEP 5

For g(x)=x+4 g(x) = \sqrt{x+4} , determine the domain.
The expression under the square root, x+4 x+4 , must be non-negative for the function to be defined.
x+40 x + 4 \geq 0

STEP 6

Solve the inequality for the domain of g(x) g(x) .
x4 x \geq -4 Thus, the domain of g(x) g(x) is [4,) [-4, \infty) .

STEP 7

Identify the range of g(x)=x+4 g(x) = \sqrt{x+4} .
Since the square root function produces non-negative outputs, the range is:
[0,) [0, \infty)

STEP 8

Graph f(x)=x3 f(x) = \sqrt{x-3} .
1. The graph starts at the point (3,0) (3, 0) .
2. The graph is a half-parabola opening to the right.
3. As x x increases, f(x) f(x) increases.

STEP 9

Graph g(x)=x+4 g(x) = \sqrt{x+4} .
1. The graph starts at the point (4,0) (-4, 0) .
2. The graph is a half-parabola opening to the right.
3. As x x increases, g(x) g(x) increases.

STEP 10

Assumptions for Problem 12
1. We are given the equation 35x+63=18 3 \sqrt[3]{5x+6} = 18 .
2. We need to solve for x x .
3. We need to check the solution.

STEP 11

Isolate the cube root on one side of the equation.
5x+63=183 \sqrt[3]{5x+6} = \frac{18}{3}

STEP 12

Simplify the right side of the equation.
5x+63=6 \sqrt[3]{5x+6} = 6

STEP 13

Cube both sides to eliminate the cube root.
5x+6=63 5x + 6 = 6^3

STEP 14

Calculate 63 6^3 .
63=216 6^3 = 216

STEP 15

Substitute back into the equation.
5x+6=216 5x + 6 = 216

STEP 16

Subtract 6 from both sides to solve for 5x 5x .
5x=2166 5x = 216 - 6

STEP 17

Calculate the right side.
5x=210 5x = 210

STEP 18

Divide both sides by 5 to solve for x x .
x=2105 x = \frac{210}{5}

STEP 19

Calculate the value of x x .
x=42 x = 42

STEP 20

Check the solution by substituting x=42 x = 42 back into the original equation.
35(42)+63=18 3 \sqrt[3]{5(42) + 6} = 18

STEP 21

Calculate inside the cube root.
3210+63=18 3 \sqrt[3]{210 + 6} = 18

STEP 22

Simplify inside the cube root.
32163=18 3 \sqrt[3]{216} = 18

STEP 23

Calculate the cube root of 216.
2163=6 \sqrt[3]{216} = 6

STEP 24

Multiply by 3 to check the left side of the original equation.
3×6=18 3 \times 6 = 18

SOLUTION

Since both sides of the equation are equal, the solution x=42 x = 42 is verified.

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