Math  /  Calculus

QuestionFor the given function, find f(x+h)f(x)h\frac{f(x+h)-f(x)}{h}. f(x)=2x2+4f(x)=2 x^{2}+4 f(x+h)f(x)h=\frac{f(x+h)-f(x)}{h}= \square (Simplify your answer.)

Studdy Solution

STEP 1

1. The function given is f(x)=2x2+4 f(x) = 2x^2 + 4 .
2. We need to find the difference quotient f(x+h)f(x)h \frac{f(x+h)-f(x)}{h} .
3. The difference quotient is a fundamental concept in calculus that approximates the derivative of a function as h h approaches 0.

STEP 2

1. Substitute x+h x+h into the function f(x) f(x) .
2. Calculate f(x+h)f(x) f(x+h) - f(x) .
3. Divide the result by h h and simplify the expression.

STEP 3

Substitute x+h x+h into the function f(x) f(x) .
f(x+h)=2(x+h)2+4 f(x+h) = 2(x+h)^2 + 4

STEP 4

Expand the expression (x+h)2 (x+h)^2 .
(x+h)2=x2+2xh+h2 (x+h)^2 = x^2 + 2xh + h^2

STEP 5

Substitute the expanded form back into the function.
f(x+h)=2(x2+2xh+h2)+4 f(x+h) = 2(x^2 + 2xh + h^2) + 4

STEP 6

Distribute the 2 in the expression.
f(x+h)=2x2+4xh+2h2+4 f(x+h) = 2x^2 + 4xh + 2h^2 + 4

STEP 7

Calculate f(x+h)f(x) f(x+h) - f(x) .
f(x+h)f(x)=(2x2+4xh+2h2+4)(2x2+4) f(x+h) - f(x) = (2x^2 + 4xh + 2h^2 + 4) - (2x^2 + 4)

STEP 8

Simplify the expression by canceling out the common terms.
f(x+h)f(x)=4xh+2h2 f(x+h) - f(x) = 4xh + 2h^2

STEP 9

Divide the simplified expression by h h .
f(x+h)f(x)h=4xh+2h2h \frac{f(x+h) - f(x)}{h} = \frac{4xh + 2h^2}{h}

STEP 10

Simplify the fraction by dividing each term by h h .
f(x+h)f(x)h=4x+2h \frac{f(x+h) - f(x)}{h} = 4x + 2h
Solution: f(x+h)f(x)h=4x+2h \frac{f(x+h) - f(x)}{h} = 4x + 2h

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