Math  /  Data & Statistics

QuestionFor the probability mass function f(x,y)=x+y250\mathrm{f}(\mathrm{x}, \mathrm{y})=\frac{x+y}{250} for x=3,4,5,6,7x=3,4,5,6,7 and y=3,4,5,6,7y=3,4,5,6,7
Find P(X=3Y=7)P(X=3 \mid Y=7) (Write in the form of an integer)

Studdy Solution

STEP 1

1. The joint probability mass function is given by f(x,y)=x+y250 f(x, y) = \frac{x+y}{250} .
2. We need to find the conditional probability P(X=3Y=7) P(X=3 \mid Y=7) .
3. The conditional probability P(X=xY=y) P(X=x \mid Y=y) is given by P(X=x,Y=y)P(Y=y) \frac{P(X=x, Y=y)}{P(Y=y)} .

STEP 2

1. Calculate P(X=3,Y=7) P(X=3, Y=7) .
2. Calculate P(Y=7) P(Y=7) .
3. Compute P(X=3Y=7) P(X=3 \mid Y=7) .

STEP 3

Calculate P(X=3,Y=7) P(X=3, Y=7) using the joint probability mass function:
P(X=3,Y=7)=f(3,7)=3+7250=10250=125 P(X=3, Y=7) = f(3, 7) = \frac{3+7}{250} = \frac{10}{250} = \frac{1}{25}

STEP 4

Calculate P(Y=7) P(Y=7) , which is the sum of probabilities for all x x values when y=7 y=7 :
P(Y=7)=x=37f(x,7) P(Y=7) = \sum_{x=3}^{7} f(x, 7)
Calculate each term:
f(3,7)=10250 f(3, 7) = \frac{10}{250} f(4,7)=11250 f(4, 7) = \frac{11}{250} f(5,7)=12250 f(5, 7) = \frac{12}{250} f(6,7)=13250 f(6, 7) = \frac{13}{250} f(7,7)=14250 f(7, 7) = \frac{14}{250}
Sum these probabilities:
P(Y=7)=10250+11250+12250+13250+14250=60250=625 P(Y=7) = \frac{10}{250} + \frac{11}{250} + \frac{12}{250} + \frac{13}{250} + \frac{14}{250} = \frac{60}{250} = \frac{6}{25}

STEP 5

Compute P(X=3Y=7) P(X=3 \mid Y=7) using the formula for conditional probability:
P(X=3Y=7)=P(X=3,Y=7)P(Y=7)=125625=16 P(X=3 \mid Y=7) = \frac{P(X=3, Y=7)}{P(Y=7)} = \frac{\frac{1}{25}}{\frac{6}{25}} = \frac{1}{6}
Convert to an integer form:
P(X=3Y=7)=0 P(X=3 \mid Y=7) = 0
The conditional probability P(X=3Y=7) P(X=3 \mid Y=7) is:
0 \boxed{0}

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