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Math Snap
PROBLEM
f(x)=−3x2+2x+3Round to the nearest hundredth if necessary. If there is more than one x-intercept, separate them If applicable, click on "None". \begin{tabular}{|ll|}
\hline vertex: & (II, □ \\
x-intercept(s): & □ \\
\hline
\end{tabular}
STEP 1
1. The function given is a quadratic function of the form f(x)=ax2+bx+c. 2. The vertex of a quadratic function in standard form can be found using the formula x=−2ab. 3. The x-intercepts (roots) of the quadratic function can be found using the quadratic formula x=2a−b±b2−4ac.
STEP 2
1. Identify the coefficients a, b, and c. 2. Calculate the vertex of the quadratic function. 3. Calculate the x-intercepts using the quadratic formula.
STEP 3
Identify the coefficients from the quadratic function f(x)=−3x2+2x+3. Here, a=−3, b=2, and c=3.
STEP 4
Calculate the x-coordinate of the vertex using the formula x=−2ab. x=−2(−3)2=−6−2=31
STEP 5
Substitute x=31 into the function to find the y-coordinate of the vertex. f(31)=−3(31)2+2(31)+3=−3(91)+32+3=−31+32+3=31+3=31+39=310The vertex is (31,310).
STEP 6
Calculate the x-intercepts using the quadratic formula x=2a−b±b2−4ac. First, calculate the discriminant: b2−4ac=22−4(−3)(3)=4+36=40
SOLUTION
Substitute the discriminant into the quadratic formula: x=2(−3)−2±40=−6−2±40Simplify 40: 40=4×10=210x=−6−2±210=−6−2±−6210=31∓310The x-intercepts are: x=31+10andx=31−10Calculate these values to the nearest hundredth: x≈31+3.16≈34.16≈1.39x≈31−3.16≈3−2.16≈−0.72The vertex is (31,310)≈(0.33,3.33). The x-intercepts are approximately 1.39 and −0.72.