Math

QuestionFind (km)(x)(k \circ m)(x) and (mk)(x)(m \circ k)(x) for k(x)=9x5k(x)=9x-5 and m(x)=x2m(x)=x^2. Are they equal?

Studdy Solution

STEP 1

Assumptions1. We are given two functions k(x)=9x5k(x)=9x-5 and m(x)=xm(x)=x^{}. . We need to find the composition of these functions, denoted as (km)(x)(k \circ m)(x).

STEP 2

The composition of functions is defined as the application of one function to the result of another. Mathematically, it can be represented as follows(km)(x)=k(m(x))(k \circ m)(x) = k(m(x))

STEP 3

We know that m(x)=x2m(x) = x^{2}. So, we need to substitute m(x)m(x) into the function k(x)k(x).
k(m(x))=k(x2)k(m(x)) = k(x^{2})

STEP 4

Now, substitute x2x^{2} into k(x)k(x) in place of xx.
k(x2)=9(x2)k(x^{2}) =9(x^{2}) -

STEP 5

implify the expression to find the result of (km)(x)(k \circ m)(x).
(km)(x)=9x25(k \circ m)(x) =9x^{2} -5So, (km)(x)=9x25(k \circ m)(x) =9x^{2} -5.

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