Math

Question Calculate a2bcb+c\frac{a^{2}-bc}{b+c} given a=4,b=2,c=3a=4, b=-2, c=3. [2 marks]

Studdy Solution

STEP 1

Assumptions1. The value of aa is4. The value of bb is -3. The value of cc is3

STEP 2

First, we need to substitute the given values of aa, bb, and cc into the expression a2bcb+c\frac{a^{2}-b c}{b+c}.
a2bcb+c=42(2)2+\frac{a^{2}-b c}{b+c} = \frac{4^{2}-(-2) \cdot}{-2+}

STEP 3

Next, we calculate the numerator and the denominator separately. First, calculate the numerator 2(2)3^{2}-(-2) \cdot3.
2(2)3=16(6)^{2}-(-2) \cdot3 =16 - (-6)

STEP 4

implify the numerator.
16(6)=16+6=2216 - (-6) =16 +6 =22

STEP 5

Now, calculate the denominator 2+3-2+3.
2+3=1-2+3 =1

STEP 6

Now that we have the numerator and the denominator, we can divide them to find the value of the expression.
221=22\frac{22}{1} =22The value of a2bcb+c\frac{a^{2}-b c}{b+c} is22.

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