Math  /  Algebra

QuestionGiven that g(x)=3x24x+2\mathrm{g}(\mathrm{x})=3 \mathrm{x}^{2}-4 \mathrm{x}+2, find each of the following. a) g(0)g(0) b) g(2)g(-2) c) g(3)g(3) d) g(x)g(-x) e) g(1t)g(1-t)

Studdy Solution

STEP 1

1. The function g(x)=3x24x+2\mathrm{g}(\mathrm{x})=3 \mathrm{x}^{2}-4 \mathrm{x}+2 is a quadratic polynomial.
2. To find g(x)\mathrm{g}(\mathrm{x}) at specific values, we substitute the given value into the function and simplify.
3. For part (d) and (e), we substitute x-x and 1t1-t respectively into the function and simplify.

STEP 2

1. Evaluate g(0)g(0) by substituting 00 into the function.
2. Evaluate g(2)g(-2) by substituting 2-2 into the function.
3. Evaluate g(3)g(3) by substituting 33 into the function.
4. Evaluate g(x)g(-x) by substituting x-x into the function.
5. Evaluate g(1t)g(1-t) by substituting 1t1-t into the function.

STEP 3

Evaluate g(0)g(0).
g(0)=3(0)24(0)+2=2 g(0) = 3(0)^2 - 4(0) + 2 = 2

STEP 4

Evaluate g(2)g(-2).
g(2)=3(2)24(2)+2 g(-2) = 3(-2)^2 - 4(-2) + 2

STEP 5

Simplify the expression for g(2)g(-2).
g(2)=3(4)+8+2=12+8+2=22 g(-2) = 3(4) + 8 + 2 = 12 + 8 + 2 = 22

STEP 6

Evaluate g(3)g(3).
g(3)=3(3)24(3)+2 g(3) = 3(3)^2 - 4(3) + 2

STEP 7

Simplify the expression for g(3)g(3).
g(3)=3(9)12+2=2712+2=17 g(3) = 3(9) - 12 + 2 = 27 - 12 + 2 = 17

STEP 8

Evaluate g(x)g(-x) by substituting x-x into the function g(x)g(x).
g(x)=3(x)24(x)+2 g(-x) = 3(-x)^2 - 4(-x) + 2

STEP 9

Simplify the expression for g(x)g(-x).
g(x)=3x2+4x+2 g(-x) = 3x^2 + 4x + 2

STEP 10

Evaluate g(1t)g(1-t) by substituting 1t1-t into the function g(x)g(x).
g(1t)=3(1t)24(1t)+2 g(1-t) = 3(1-t)^2 - 4(1-t) + 2

STEP 11

Expand and simplify the expression for g(1t)g(1-t).
g(1t)=3(12t+t2)4(1t)+2 g(1-t) = 3(1 - 2t + t^2) - 4(1 - t) + 2 =36t+3t24+4t+2 = 3 - 6t + 3t^2 - 4 + 4t + 2 =3t22t+1 = 3t^2 - 2t + 1
The solutions are: a) g(0)=2g(0) = 2 b) g(2)=22g(-2) = 22 c) g(3)=17g(3) = 17 d) g(x)=3x2+4x+2g(-x) = 3x^2 + 4x + 2 e) g(1t)=3t22t+1g(1-t) = 3t^2 - 2t + 1

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