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QuestionFind f(x)=95x+32f(x)=\frac{9}{5} x+32. Calculate f(60)f(60), f(0)f(0), and f(25)f(25).

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=95x+32f(x)=\frac{9}{5} x+32 . We need to find the values of f(60)f(60), f(0)f(0), and f(25)f(25)

STEP 2

To find the value of f(60)f(60), we substitute x=60x=60 into the function.
f(60)=95×60+32f(60)=\frac{9}{5} \times60+32

STEP 3

Calculate the value of f(60)f(60).
f(60)=95×60+32=108+32=140f(60)=\frac{9}{5} \times60+32 =108+32 =140

STEP 4

To find the value of f(0)f(0), we substitute x=0x=0 into the function.
f(0)=9×0+32f(0)=\frac{9}{} \times0+32

STEP 5

Calculate the value of f(0)f(0).
f(0)=95×0+32=0+32=32f(0)=\frac{9}{5} \times0+32 =0+32 =32

STEP 6

To find the value of f(25)f(25), we substitute x=25x=25 into the function.
f(25)=95×25+32f(25)=\frac{9}{5} \times25+32

STEP 7

Calculate the value of f(25)f(25).
f(25)=95×25+32=45+32=77f(25)=\frac{9}{5} \times25+32 =45+32 =77So, the values of f(60)f(60), f(0)f(0), and f(25)f(25) are140,32, and77 respectively.

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