Math

QuestionFind xx such that f(x)=xf(x)=x for f(x)=34x+12f(x)=\frac{3}{4} x+12.

Studdy Solution

STEP 1

Assumptions1. The function is defined as f(x)=34x+12f(x)=\frac{3}{4} x+12 . We need to find the value of xx when f(x)=xf(x)=x

STEP 2

To find the value of xx when f(x)=xf(x)=x, we need to set f(x)f(x) equal to xx and solve for xx.
f(x)=xf(x) = x

STEP 3

Substitute the given function f(x)=3x+12f(x)=\frac{3}{} x+12 into the equation.
3x+12=x\frac{3}{} x+12 = x

STEP 4

To solve for xx, we need to get all terms involving xx on one side of the equation. Subtract 34x\frac{3}{4} x from both sides of the equation.
12=x34x12 = x - \frac{3}{4} x

STEP 5

Notice that on the right side of the equation, we have xx in terms of itself. To simplify, we can combine these terms by finding a common denominator.
12=44x34x12 = \frac{4}{4}x - \frac{3}{4} x

STEP 6

Subtract the fractions on the right side of the equation.
12=14x12 = \frac{1}{4}x

STEP 7

To isolate xx, we can multiply both sides of the equation by the reciprocal of 14\frac{1}{4}, which is 44.
12×4=x12 \times4 = x

STEP 8

Calculate the value of xx.
x=12×4=48x =12 \times4 =48The value of xx when f(x)=xf(x)=x is 4848.

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