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Math

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PROBLEM

Given the function
f(x)={x29x3x39x=3f(x) = \begin{cases} \frac{x^2 - 9}{x - 3} & x \neq 3 \\ 9 & x = 3 \end{cases}
Calculate the following values:
f(2)=f(2) =
f(0)=f(0) =
f(3)=f(3) =

STEP 1

What is this asking?
We're given a piecewise function f(x)f(x) and we need to find its value at x=2x = 2, x=0x = 0, and x=3x = 3.
Watch out!
Piecewise functions can be tricky!
Make sure to plug in the xx value into the correct piece of the function.

STEP 2

1. Evaluate f(2)f(2)
2. Evaluate f(0)f(0)
3. Evaluate f(3)f(3)

STEP 3

Since 232 \neq 3, we use the first piece of the function: f(x)=x29x3f(x) = \frac{x^2 - 9}{x - 3}.
Let's plug in x=2x = 2.
f(2)=22923 f(2) = \frac{2^2 - 9}{2 - 3}

STEP 4

Now, let's simplify the numerator and denominator:
f(2)=4923=51 f(2) = \frac{4 - 9}{2 - 3} = \frac{-5}{-1}

STEP 5

Dividing 5-5 by 1-1 gives us our result:
f(2)=5 f(2) = 5

STEP 6

Since 030 \neq 3, we again use the first piece: f(x)=x29x3f(x) = \frac{x^2 - 9}{x - 3}. Substitute x=0x = 0.
f(0)=02903 f(0) = \frac{0^2 - 9}{0 - 3}

STEP 7

Simplify the numerator and denominator:
f(0)=93 f(0) = \frac{-9}{-3}

STEP 8

Dividing 9-9 by 3-3 gives us:
f(0)=3 f(0) = 3

STEP 9

Now, x=3x = 3, so we use the second piece of the function: f(x)=9f(x) = 9.
This one is super straightforward!
f(3)=9 f(3) = 9

SOLUTION

f(2)=5f(2) = 5
f(0)=3f(0) = 3
f(3)=9f(3) = 9

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