Math

Question Find the image coordinates of a point Q(5,1)Q(-5,1) under the transformation (x,y)(y,x)(x, y) \rightarrow(-y,-x).

Studdy Solution

STEP 1

Assumptions
1. The preimage coordinate is Q(5,1)Q(-5,1).
2. The transformation is described by the coordinate notation (x,y)(y,x)(x, y) \rightarrow(-y,-x).
3. We need to apply the transformation to the preimage to find the image coordinate QQ'.

STEP 2

Identify the components of the preimage coordinate.
The preimage coordinate is Q(5,1)Q(-5,1), where x=5x = -5 and y=1y = 1.

STEP 3

Apply the transformation to the preimage coordinate.
The transformation (x,y)(y,x)(x, y) \rightarrow(-y,-x) tells us to replace xx with y-y and yy with x-x.

STEP 4

Substitute the values of xx and yy from the preimage into the transformation.
For Q(5,1)Q(-5,1), we have x=5x = -5 and y=1y = 1. Applying the transformation:
(y,x)=((1),(5))(-y,-x) = (-(1),-(-5))

STEP 5

Calculate the new coordinates after applying the transformation.
(y,x)=(1,5)(-y,-x) = (-1,5)

STEP 6

Write down the coordinates of the image QQ'.
The image coordinate after the transformation is Q(1,5)Q'(-1,5).
Therefore, the correct answer is Q(1,5)Q^{\prime}(-1,5).

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