Math  /  Data & Statistics

QuestionGiven the table of values for g(x):\text{Given the table of values for } g(x):
xg(x)513443124113028\begin{array}{|c|c|} \hline x & g(x) \\ \hline -5 & -13 \\ \hline -4 & -4 \\ \hline -3 & -1 \\ \hline -2 & -4 \\ \hline -1 & -13 \\ \hline 0 & -28 \\ \hline \end{array}
The maximum  value of f(x) is 0 and there is no minimum  value. The maximum  value of g(x) is  and there is no minimum  value. Therefore f(x) has a  value than g(x).\text{The maximum } \vee \text{ value of } f(x) \text{ is 0 and there is no minimum } \vee \text{ value. The maximum } \vee \text{ value of } g(x) \text{ is } \square \text{ and there is no minimum } \vee \text{ value. Therefore } f(x) \text{ has a } \square \text{ value than } g(x).
Use the table and give the maximum value of g(x).\text{Use the table and give the maximum value of } g(x).

Studdy Solution

STEP 1

What is this asking? What's the biggest value of g(x)g(x) we can find in the table? Watch out! Don't get tricked by the xx values, we only care about the g(x)g(x) values!
Also, bigger negative numbers are actually smaller.

STEP 2

1. Examine the g(x)g(x) column.
2. Find the maximum value.

STEP 3

Let's look at all the values of g(x)g(x) in the table.
We've got 13-13, 4-4, 1-1, 4-4, 13-13, and 28-28.
We're on the hunt for the **maximum** value, which means the biggest number!

STEP 4

Remember, with negative numbers, the closer they are to zero, the *bigger* they are.
So, out of all the g(x)g(x) values, 1-1 is the closest to zero, making it the **largest value**.

STEP 5

The maximum value of g(x)g(x) is 1-1.
So, the maximum \vee value of g(x)g(x) is 1-1 and there is no minimum \vee value.
Since the maximum \vee value of f(x)f(x) is 00, then f(x)f(x) has a *greater* value than g(x)g(x).

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