Math

QuestionGraph the function f(x)={12x if x03 if x>0f(x)=\left\{\begin{array}{ccc}\frac{1}{2} x & \text { if } & x \leq 0 \\ 3 & \text { if } & x>0\end{array}\right. and find its range.

Studdy Solution

STEP 1

Assumptions1. The function f(x)f(x) is a piecewise function defined as 1x\frac{1}{} x for x0x \leq0 and 33 for x>0x >0. . We need to graph this function and determine its range.

STEP 2

Let's start by graphing the first piece of the function, 12x\frac{1}{2} x for x0x \leq0. This is a linear function with a slope of 12\frac{1}{2} and it is defined for all xx less than or equal to 00.

STEP 3

We can start by plotting a few points. When x=0x =0, f(x)=12×0=0f(x) = \frac{1}{2} \times0 =0. When x=1x = -1, f(x)=12×1=12f(x) = \frac{1}{2} \times -1 = -\frac{1}{2}. When x=2x = -2, f(x)=12×2=1f(x) = \frac{1}{2} \times -2 = -1.

STEP 4

Now, let's graph the second piece of the function, 33 for x>0x >0. This is a constant function and it is defined for all xx greater than 00.

STEP 5

We can plot a few points for this piece as well. When x=1x =1, f(x)=3f(x) =3. When x=2x =2, f(x)=3f(x) =3.

STEP 6

Now, let's put these two pieces together to graph the entire function. For x0x \leq0, we graph the line 12x\frac{1}{2} x and for x>0x >0, we graph the horizontal line y=3y =3.

STEP 7

The graph of the function f(x)f(x) will look like a line with slope 12\frac{1}{2} for x0x \leq0 and a horizontal line at y=3y =3 for x>0x >0.

STEP 8

Now, let's determine the range of the function. The range of a function is the set of all possible output values (y-values).

STEP 9

For the piece 2x\frac{}{2} x for xx \leq, the range is all y-values less than or equal to $$.

STEP 10

For the piece 33 for x>0x >0, the range is simply 33.

STEP 11

Putting these two pieces together, the range of the function f(x)f(x) is all y-values less than or equal to 00 and 33.
So, the range of the function is (,0]{3}(-\infty,0] \cup \{3\}.

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