QuestionGraph the line defined by the equation $y + 3 = -2(x - 4)$ .

Studdy Solution

STEP 1

Assumptions1. The equation given is in point-slope form, which is $y - y1 = m(x - x1)$ , where $m$ is the slope of the line and $(x1, y1)$ is a point on the line. . We need to graph the line given by the equation $y+3=-(x-4)$ .

STEP 2

The first step in graphing the line is to identify the slope and the point on the line from the given equation. In this case, the slope $m$ is -2 and the point $(x1, y1)$ is (4, -).

STEP 3

Next, we plot the point (, -3) on the graph. This is done by moving units to the right of the origin (for the x-coordinate) and3 units down (for the y-coordinate).

STEP 4

The slope of the line is -2, which means for every1 unit we move to the right on the x-axis, we move2 units down on the y-axis.

STEP 5

Starting from the point (4, -3), we can use the slope to find another point on the line. Since the slope is -2, we move1 unit to the right and2 units down. This gives us the point (5, -5).

STEP 6

Plot the point (5, -5) on the graph.

STEP 7

Draw a straight line through the points (4, -3) and (5, -5). This line represents the equation $y+3=-2(x-4)$ .

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QuestionGraph the line defined by the equation $y + 3 = -2(x - 4)$ .

Studdy Solution

STEP 1

Assumptions1. The equation given is in point-slope form, which is $y - y1 = m(x - x1)$ , where $m$ is the slope of the line and $(x1, y1)$ is a point on the line. . We need to graph the line given by the equation $y+3=-(x-4)$ .

STEP 2

The first step in graphing the line is to identify the slope and the point on the line from the given equation. In this case, the slope $m$ is -2 and the point $(x1, y1)$ is (4, -).

STEP 3

Next, we plot the point (, -3) on the graph. This is done by moving units to the right of the origin (for the x-coordinate) and3 units down (for the y-coordinate).

STEP 4

The slope of the line is -2, which means for every1 unit we move to the right on the x-axis, we move2 units down on the y-axis.

STEP 5

Starting from the point (4, -3), we can use the slope to find another point on the line. Since the slope is -2, we move1 unit to the right and2 units down. This gives us the point (5, -5).

STEP 6

Plot the point (5, -5) on the graph.

STEP 7

Draw a straight line through the points (4, -3) and (5, -5). This line represents the equation $y+3=-2(x-4)$ .

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QuestionGraph the line defined by the equation y+3=−2(x−4)y + 3 = -2(x - 4)y+3=−2(x−4).

Studdy Solution

STEP 1

Assumptions1. The equation given is in point-slope form, which is y−y1=m(x−x1)y - y1 = m(x - x1)y−y1=m(x−x1), where mmm is the slope of the line and (x1,y1)(x1, y1)(x1,y1) is a point on the line. . We need to graph the line given by the equation y+3=−(x−4)y+3=-(x-4)y+3=−(x−4).

STEP 2

The first step in graphing the line is to identify the slope and the point on the line from the given equation. In this case, the slope mmm is -2 and the point (x1,y1)(x1, y1)(x1,y1) is (4, -).

STEP 3

Next, we plot the point (, -3) on the graph. This is done by moving units to the right of the origin (for the x-coordinate) and3 units down (for the y-coordinate).

STEP 4

The slope of the line is -2, which means for every1 unit we move to the right on the x-axis, we move2 units down on the y-axis.

STEP 5

Starting from the point (4, -3), we can use the slope to find another point on the line. Since the slope is -2, we move1 unit to the right and2 units down. This gives us the point (5, -5).

STEP 6

Plot the point (5, -5) on the graph.

STEP 7

Draw a straight line through the points (4, -3) and (5, -5). This line represents the equation y+3=−2(x−4)y+3=-2(x-4)y+3=−2(x−4).

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Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionGraph the line defined by the equation $y + 3 = -2(x - 4)$ .

Assumptions1. The equation given is in point-slope form, which is $y - y1 = m(x - x1)$ , where $m$ is the slope of the line and $(x1, y1)$ is a point on the line. . We need to graph the line given by the equation $y+3=-(x-4)$ .

The first step in graphing the line is to identify the slope and the point on the line from the given equation. In this case, the slope $m$ is -2 and the point $(x1, y1)$ is (4, -).

Draw a straight line through the points (4, -3) and (5, -5). This line represents the equation $y+3=-2(x-4)$ .