Math

QuestionGraph the line with a yy-intercept of -3 and a slope of 14\frac{1}{4}.

Studdy Solution

STEP 1

Assumptions1. The y-intercept of the line is -3. The slope of the line is 14\frac{1}{4}

STEP 2

The equation of a line in slope-intercept form is given by y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.

STEP 3

Substitute the given slope and y-intercept into the equation of the line.
y=1x3y = \frac{1}{}x -3

STEP 4

To graph the line, we start by plotting the y-intercept. The y-intercept is the point where the line crosses the y-axis. In this case, the y-intercept is -3, so we plot a point at (0, -3) on the graph.

STEP 5

The slope of the line is 14\frac{1}{4}, which means that for every4 units we move to the right along the x-axis, we move up1 unit along the y-axis. Starting from the y-intercept, we can plot additional points by moving to the right4 units and up1 unit each time.

STEP 6

After plotting several points, we can draw a line through them. This line represents the equation y=14x3y = \frac{1}{4}x -3.
The graph of the line with y-intercept -3 and slope 14\frac{1}{4} is a straight line that crosses the y-axis at -3 and rises at a rate of1 unit vertically for every4 units horizontally.

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