Math  /  Algebra

Questiong(x)={2x+3,x>42x+3,x4g(x) = \begin{cases} 2x+3, & x > 4 \\ -2x+3, & x \le 4 \end{cases}
What is g(7)g(7) if:
13 -13 17 -17

Studdy Solution

STEP 1

What is this asking? We're given a *piecewise function* g(x)g(x), which means it acts differently depending on the input xx, and we need to find what g(7)g(7) is! Watch out! Make sure to plug the xx value into the *correct* piece of the function!
It's easy to get mixed up!

STEP 2

1. Determine the relevant piece
2. Evaluate g(7)g(7)

STEP 3

Alright, so we have this *funky* function g(x)g(x) that changes its outfit depending on the value of xx.
When xx is greater than **4**, g(x)g(x) dresses up as 2x+32x + 3.
But when xx is less than or equal to **4**, it prefers the disguise 2x+3-2x + 3.

STEP 4

We're trying to find g(7)g(7).
So our xx value is **7**.
Since **7** is *definitely* greater than **4**, we know which piece to use: the 2x+32x + 3 one!

STEP 5

Now, let's **plug in** our xx value, which is **7**, into the *correct* piece of the function.
Remember, we decided that since x=7x=7 is greater than 4, we're using g(x)=2x+3g(x) = 2x + 3.

STEP 6

So, we **substitute** x=7x=7 into the expression: g(7)=27+3g(7) = 2 \cdot 7 + 3

STEP 7

First, we **multiply**: 27=142 \cdot 7 = 14

STEP 8

Then, we **add**: 14+3=1714 + 3 = 17

STEP 9

So, our **final result** is: g(7)=17g(7) = 17

STEP 10

g(7)=17g(7) = 17

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