Math / Data & Statistics

Questionwww-awualeks.com Unitiled document -.. Traditional | Stats I N... Defense | Stats | NBA... Utah vs LA Stats \& P... Ivica Zubac /// Stats /... Home - Northern Ess... Content Midterm Exam: Ch $1(1,2) 2(1,2,3) 3(1,2,3) 4(1,2) 5(1,2,3) G(1,2)$ Question 12 of 30 (1 point) I Question Attempt: 1 of 1 Time Remaining: 1:50:51 Jonath:
Hamburgers: A news story reported the number of calories in hamburgers from six fast-food restaurants. The results are: $\begin{array}{llllll} 280 & 310 & 290 & 330 & 260 & 340 \end{array}$
Part: $0 / 3$
Part 1 of 3 (a) Find the mean number of calories. Round the answer to one decimal place as needed.
The mean number of calories is 301.7 .
Part: $1 / 3$
Part 2 of 3 (b) Find the median number of calories. Round the answer to one decimal place as needed.
The median number of calories is 300 .
Part: $2 / 3$
Part 3 of 3 (c) The Impossible Burger, a plant-based burger, sold at some fast-food restaurants has 240 calories. Find the mean and median if the Impossible Burger is included. Round the answers to one decimal place as needed.
If the Impossible Burger is included, the mean number of calories is $\square$ .
If the Impossible Burger is included, the median number of calories is $\square$ Continue Submit Assignm (5) 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use 1 Privacy Center I Access

Studdy Solution

STEP 1

What is this asking? We need to find the mean and median number of calories for a group of hamburgers, and then recalculate these values if we add a new burger with fewer calories to the mix! Watch out! Don't forget to put the numbers in order before finding the median!
Also, remember that the median might be a number in the list, or it might be the average of two numbers.

STEP 2

1. Find the initial mean.
2. Find the initial median.
3. Find the new mean.
4. Find the new median.

STEP 3

Let's add up all the calorie counts: $280 + 310 + 290 + 330 + 260 + 340 = 1810$ .

STEP 4

Now, divide this sum by the number of burgers, which is 6: $1810 / 6 = 301.666...$ .

STEP 5

Rounding to one decimal place gives us a mean of 301.7 calories.

STEP 6

First, let's arrange the calorie counts from least to greatest: $260, 280, 290, 310, 330, 340$ .

STEP 7

Since there are an even number of values, the median is the average of the two middle numbers: $290$ and $310$ .

STEP 8

The median is $(290 + 310) / 2 = 600 / 2 = 300$ .
So, the median number of calories is 300.

STEP 9

Let's add the Impossible Burger's $240$ calories to our previous total: $1810 + 240 = 2050$ .

STEP 10

Now we have 7 burgers, so divide the new total by $7$ : $2050 / 7 = 292.857...$ .

STEP 11

Rounding to one decimal place, the new mean is 292.9 calories.

STEP 12

Let's put all the calorie counts in order, including the Impossible Burger: $240, 260, 280, 290, 310, 330, 340$ .

STEP 13

Now we have an odd number of values, so the median is simply the middle value, which is 290.

STEP 14

The mean with the Impossible Burger is 292.9 calories.
The median with the Impossible Burger is 290 calories.

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Studdy Solution

STEP 1

STEP 2

1. Find the initial mean.
2. Find the initial median.
3. Find the new mean.
4. Find the new median.

STEP 3

Let's add up all the calorie counts: $280 + 310 + 290 + 330 + 260 + 340 = 1810$ .

STEP 4

Now, divide this sum by the number of burgers, which is 6: $1810 / 6 = 301.666...$ .

STEP 5

Rounding to one decimal place gives us a mean of 301.7 calories.

STEP 6

First, let's arrange the calorie counts from least to greatest: $260, 280, 290, 310, 330, 340$ .

STEP 7

Since there are an even number of values, the median is the average of the two middle numbers: $290$ and $310$ .

STEP 8

The median is $(290 + 310) / 2 = 600 / 2 = 300$ .
So, the median number of calories is 300.

STEP 9

Let's add the Impossible Burger's $240$ calories to our previous total: $1810 + 240 = 2050$ .

STEP 10

Now we have 7 burgers, so divide the new total by $7$ : $2050 / 7 = 292.857...$ .

STEP 11

Rounding to one decimal place, the new mean is 292.9 calories.

STEP 12

Let's put all the calorie counts in order, including the Impossible Burger: $240, 260, 280, 290, 310, 330, 340$ .

STEP 13

Now we have an odd number of values, so the median is simply the middle value, which is 290.

STEP 14

The mean with the Impossible Burger is 292.9 calories.
The median with the Impossible Burger is 290 calories.

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Studdy Solution

STEP 1

STEP 2

1. Find the initial mean.2. Find the initial median.3. Find the new mean.4. Find the new median.

STEP 3

Let's **add up** all the calorie counts: 280+310+290+330+260+340=1810280 + 310 + 290 + 330 + 260 + 340 = 1810280+310+290+330+260+340=1810.

STEP 4

Now, **divide** this sum by the number of burgers, which is **6**: 1810/6=301.666...1810 / 6 = 301.666...1810/6=301.666....

STEP 5

Rounding to one decimal place gives us a mean of **301.7** calories.

STEP 6

First, let's **arrange** the calorie counts from least to greatest: 260,280,290,310,330,340260, 280, 290, 310, 330, 340260,280,290,310,330,340.

STEP 7

Since there are an **even** number of values, the median is the **average** of the two middle numbers: 290290290 and 310310310.

STEP 8

The median is (290+310)/2=600/2=300(290 + 310) / 2 = 600 / 2 = 300(290+310)/2=600/2=300.So, the **median** number of calories is **300**.

STEP 9

Let's **add** the Impossible Burger's 240240240 calories to our previous total: 1810+240=20501810 + 240 = 20501810+240=2050.

STEP 10

Now we have **7** burgers, so **divide** the new total by 777: 2050/7=292.857...2050 / 7 = 292.857...2050/7=292.857....

STEP 11

Rounding to one decimal place, the new mean is **292.9** calories.

STEP 12

Let's **put** all the calorie counts in order, including the Impossible Burger: 240,260,280,290,310,330,340240, 260, 280, 290, 310, 330, 340240,260,280,290,310,330,340.

STEP 13

Now we have an **odd** number of values, so the median is simply the middle value, which is **290**.

STEP 14

The mean with the Impossible Burger is **292.9** calories.The median with the Impossible Burger is **290** calories.

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1. Find the initial mean.
2. Find the initial median.
3. Find the new mean.
4. Find the new median.

Let's add up all the calorie counts: $280 + 310 + 290 + 330 + 260 + 340 = 1810$ .

Now, divide this sum by the number of burgers, which is 6: $1810 / 6 = 301.666...$ .

Rounding to one decimal place gives us a mean of 301.7 calories.

First, let's arrange the calorie counts from least to greatest: $260, 280, 290, 310, 330, 340$ .

Since there are an even number of values, the median is the average of the two middle numbers: $290$ and $310$ .

The median is $(290 + 310) / 2 = 600 / 2 = 300$ .
So, the median number of calories is 300.

Let's add the Impossible Burger's $240$ calories to our previous total: $1810 + 240 = 2050$ .

Now we have 7 burgers, so divide the new total by $7$ : $2050 / 7 = 292.857...$ .

Rounding to one decimal place, the new mean is 292.9 calories.

Let's put all the calorie counts in order, including the Impossible Burger: $240, 260, 280, 290, 310, 330, 340$ .

Now we have an odd number of values, so the median is simply the middle value, which is 290.

The mean with the Impossible Burger is 292.9 calories.
The median with the Impossible Burger is 290 calories.