Math  /  Data & Statistics

QuestionHeights ( cm ) and weights ( kg ) are measured for 100 randomly selected adult males, and range from heights of 139 to 193 cm and weights of 38 to 150 kg . Let the predictor variable x be the first variable given. The 100 paired measurements yield xˉ=167.54 cm,yˉ=81.44 kg,r=0.185,P\bar{x}=167.54 \mathrm{~cm}, \bar{y}=81.44 \mathrm{~kg}, \mathrm{r}=0.185, P-value =0.065=0.065, and y^=107+1.05x\hat{y}=-107+1.05 x. Find the best predicted value of y^\hat{y} (weight) given an adult male who is 161 cm tall. Use a 0.05 significance level.
Click the icon to view the critical values of the Pearson correlation coefficient rr.
The best predicted value of y^\hat{y} for an adult male who is 161 cm tall is \square kg . (Round to two decimal places as needed.)

Studdy Solution

STEP 1

What is this asking? If a dude is 161 cm tall, how heavy do we think he is, based on data from 100 other dudes? Watch out! The *P*-value is greater than the significance level, so the correlation isn't statistically significant.
This means our prediction might not be super reliable!

STEP 2

1. Check the significance
2. Make the prediction

STEP 3

Our *P*-value is 0.0650.065, which is *larger* than our significance level of 0.050.05.

STEP 4

This means the correlation between height and weight isn't statistically significant.
So, using the regression equation might not be the best way to predict weight.

STEP 5

Even though the correlation isn't significant, the problem still wants us to use the equation.
We're given the equation y^=107+1.05x\hat{y} = -107 + 1.05x, where xx is the height.
We want to predict the weight y^\hat{y} when x=161x = 161 cm.
Let's plug it in: y^=107+1.05161\hat{y} = -107 + 1.05 \cdot 161.

STEP 6

y^=107+169.05\hat{y} = -107 + 169.05.
So, y^=62.05\hat{y} = 62.05.

STEP 7

The best predicted weight for a 161 cm tall adult male is **62.05** kg.

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