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Homework \# 4:
Question 21 of 40 (1 point) I Question Attempt: 1 of 3
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Student loans: The Institute for College Access and Success reported that of college students in a recent year graduated with student loan debt. A random sample of 90 graduates is drawn. Round your answers to at least four decimal places if necessary.
Part 1 of 6
(a) Find the mean .
The mean is 0.65 .
Part 2 of 6
(b) Find the standard deviation .
The standard deviation is 0.0503 .
Part:
Part 3 of 6
(c) Find the probability that less than of the people in the sample were in debt.
The probability that less than of the people in the sample were in debt is .
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Studdy Solution
STEP 1
What is this asking? We're looking at the probability that less than 52% of a group of 90 recent graduates have student loan debt, knowing that 65% of all graduates typically do. Watch out! Don't forget to convert percentages to decimals before calculating, and make sure to use the sample size correctly in your calculations!
STEP 2
1. Calculate the z-score.
2. Find the probability associated with the z-score.
STEP 3
We're interested in the probability that *less* than 52% of the sample has debt.
So our **target proportion** is .
STEP 4
From the problem, we know the **mean** proportion of graduates with debt is , and the **standard deviation** is .
STEP 5
The z-score tells us how many standard deviations our **target proportion** is away from the **mean**.
The formula is:
Plugging in our values:
So our **z-score** is approximately .
This means our **target proportion** of is standard deviations *below* the **mean** of .
STEP 6
A z-score of corresponds to a probability.
We can look this up in a z-table (negative z-scores are usually in a separate table) or use a calculator with a built-in z-score function.
STEP 7
Looking up in the z-table, we find a probability of approximately .
This is the probability of getting a sample with a proportion of graduates in debt less than .
STEP 8
The probability that less than 52% of the people in the sample were in debt is approximately .
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