QuestionCalculate moles of $\mathrm{CH}_{3} \mathrm{OH}$ in $150.0 \mathrm{~mL}$ of $0.210 \mathrm{M} \mathrm{CH}_{3} \mathrm{OH}$ .

Studdy Solution

STEP 1

Assumptions1. The volume of $\mathrm{CH}_{3} \mathrm{OH}$ is $150.0 \mathrm{~m}$ . The molarity of $\mathrm{CH}_{3} \mathrm{OH}$ is $0.210 \mathrm{M}$

STEP 2

First, we need to convert the volume from milliliters to liters, as molarity is defined as moles per liter.
$Volume\, in\, liters = Volume\, in\, milliliters /1000$

STEP 3

Now, plug in the given value for the volume in milliliters to calculate the volume in liters.
$Volume\, in\, liters =150.0 \mathrm{~m} /1000$

STEP 4

Calculate the volume in liters.
$Volume\, in\, liters =150.0 \mathrm{~m} /1000 =0.150 \mathrm{~}$

STEP 5

Now that we have the volume in liters, we can find the quantity in moles. This can be done by multiplying the volume in liters by the molarity.
$Quantity\, in\, moles = Volume\, in\, liters \\times Molarity$

STEP 6

Plug in the values for the volume in liters and the molarity to calculate the quantity in moles.
$Quantity\, in\, moles =0.150 \mathrm{~} \\times0.210 \mathrm{M}$

STEP 7

Calculate the quantity in moles.
$Quantity\, in\, moles =0.150 \mathrm{~} \\times0.210 \mathrm{M} =0.0315 \mathrm{~moles}$ The quantity in moles of $\mathrm{CH}_{3} \mathrm{OH}$ in $150.0 \mathrm{~m}$ of $0.210 \mathrm{M} \mathrm{CH}_{3} \mathrm{OH}$ is $0.0315 \mathrm{~moles}$ .

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QuestionCalculate moles of $\mathrm{CH}_{3} \mathrm{OH}$ in $150.0 \mathrm{~mL}$ of $0.210 \mathrm{M} \mathrm{CH}_{3} \mathrm{OH}$ .

Studdy Solution

STEP 1

Assumptions1. The volume of $\mathrm{CH}_{3} \mathrm{OH}$ is $150.0 \mathrm{~m}$ . The molarity of $\mathrm{CH}_{3} \mathrm{OH}$ is $0.210 \mathrm{M}$

STEP 2

First, we need to convert the volume from milliliters to liters, as molarity is defined as moles per liter.
$Volume\, in\, liters = Volume\, in\, milliliters /1000$

STEP 3

Now, plug in the given value for the volume in milliliters to calculate the volume in liters.
$Volume\, in\, liters =150.0 \mathrm{~m} /1000$

STEP 4

Calculate the volume in liters.
$Volume\, in\, liters =150.0 \mathrm{~m} /1000 =0.150 \mathrm{~}$

STEP 5

Now that we have the volume in liters, we can find the quantity in moles. This can be done by multiplying the volume in liters by the molarity.
$Quantity\, in\, moles = Volume\, in\, liters \\times Molarity$

STEP 6

Plug in the values for the volume in liters and the molarity to calculate the quantity in moles.
$Quantity\, in\, moles =0.150 \mathrm{~} \\times0.210 \mathrm{M}$

STEP 7

Calculate the quantity in moles.
$Quantity\, in\, moles =0.150 \mathrm{~} \\times0.210 \mathrm{M} =0.0315 \mathrm{~moles}$ The quantity in moles of $\mathrm{CH}_{3} \mathrm{OH}$ in $150.0 \mathrm{~m}$ of $0.210 \mathrm{M} \mathrm{CH}_{3} \mathrm{OH}$ is $0.0315 \mathrm{~moles}$ .

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QuestionCalculate moles of CH3OH\mathrm{CH}_{3} \mathrm{OH}CH3​OH in 150.0 mL150.0 \mathrm{~mL}150.0 mL of 0.210MCH3OH0.210 \mathrm{M} \mathrm{CH}_{3} \mathrm{OH}0.210MCH3​OH.

Studdy Solution

STEP 1

Assumptions1. The volume of CH3OH\mathrm{CH}_{3} \mathrm{OH}CH3​OH is 150.0 m150.0 \mathrm{~m}150.0 m . The molarity of CH3OH\mathrm{CH}_{3} \mathrm{OH}CH3​OH is 0.210M0.210 \mathrm{M}0.210M

STEP 2

First, we need to convert the volume from milliliters to liters, as molarity is defined as moles per liter.Volume in liters=Volume in milliliters/1000Volume\, in\, liters = Volume\, in\, milliliters /1000Volumeinliters=Volumeinmilliliters/1000

STEP 3

Now, plug in the given value for the volume in milliliters to calculate the volume in liters.Volume in liters=150.0 m/1000Volume\, in\, liters =150.0 \mathrm{~m} /1000Volumeinliters=150.0 m/1000

STEP 4

Calculate the volume in liters.Volume in liters=150.0 m/1000=0.150 Volume\, in\, liters =150.0 \mathrm{~m} /1000 =0.150 \mathrm{~}Volumeinliters=150.0 m/1000=0.150

STEP 5

Now that we have the volume in liters, we can find the quantity in moles. This can be done by multiplying the volume in liters by the molarity.Quantity in moles=Volume in literstimesMolarityQuantity\, in\, moles = Volume\, in\, liters \\times MolarityQuantityinmoles=VolumeinliterstimesMolarity

STEP 6

Plug in the values for the volume in liters and the molarity to calculate the quantity in moles.Quantity in moles=0.150 times0.210MQuantity\, in\, moles =0.150 \mathrm{~} \\times0.210 \mathrm{M}Quantityinmoles=0.150 times0.210M

STEP 7

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QuestionCalculate moles of $\mathrm{CH}_{3} \mathrm{OH}$ in $150.0 \mathrm{~mL}$ of $0.210 \mathrm{M} \mathrm{CH}_{3} \mathrm{OH}$ .

Assumptions1. The volume of $\mathrm{CH}_{3} \mathrm{OH}$ is $150.0 \mathrm{~m}$ . The molarity of $\mathrm{CH}_{3} \mathrm{OH}$ is $0.210 \mathrm{M}$

First, we need to convert the volume from milliliters to liters, as molarity is defined as moles per liter.
$Volume\, in\, liters = Volume\, in\, milliliters /1000$

Now, plug in the given value for the volume in milliliters to calculate the volume in liters.
$Volume\, in\, liters =150.0 \mathrm{~m} /1000$

Calculate the volume in liters.
$Volume\, in\, liters =150.0 \mathrm{~m} /1000 =0.150 \mathrm{~}$

Now that we have the volume in liters, we can find the quantity in moles. This can be done by multiplying the volume in liters by the molarity.
$Quantity\, in\, moles = Volume\, in\, liters \\times Molarity$

Plug in the values for the volume in liters and the molarity to calculate the quantity in moles.
$Quantity\, in\, moles =0.150 \mathrm{~} \\times0.210 \mathrm{M}$