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Math

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PROBLEM

How many rows and columns must matrix AA have to map R8\mathbb{R}^{8} to R9\mathbb{R}^{9} using T(x)=AxT(x)=A x?
A. 9 rows, 9 columns
B. 9 rows, 8 columns
C. 8 rows, 8 columns
D. 8 rows, 9 columns

STEP 1

Assumptions1. We are given a linear transformation (x)=Ax(x)=Ax from R8\mathbb{R}^{8} to R9\mathbb{R}^{9}.
. We need to find the dimensions of the matrix AA that defines this transformation.

STEP 2

In a linear transformation defined by a matrix multiplication, the number of columns in the matrix must equal the dimension of the input space. This is because each column of the matrix corresponds to a basis vector in the input space.
Number of columns in A=Dimension of input space\text{Number of columns in } A = \text{Dimension of input space}

STEP 3

Substitute the given dimension of the input space into the equation.
Number of columns in A=8\text{Number of columns in } A =8

STEP 4

Similarly, the number of rows in the matrix must equal the dimension of the output space. This is because each row of the matrix corresponds to a basis vector in the output space.
Number of rows in A=Dimension of output space\text{Number of rows in } A = \text{Dimension of output space}

SOLUTION

Substitute the given dimension of the output space into the equation.
Number of rows in A=9\text{Number of rows in } A =9So, the matrix AA must have9 rows and8 columns. Therefore, the correct answer is B. The matrix A must have9 rows and8 columns.

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