Math

Question Find the amount of pure gold to add to a 4-ounce alloy that is 20%20\% gold to make it 55%55\% gold. Round to 2 decimal places.

Studdy Solution

STEP 1

1. The 4-ounce alloy contains 20%20\% gold, which means it contains 0.20×40.20 \times 4 ounces of gold.
2. We are adding pure gold, which is 100%100\% gold.
3. The final mixture should be 55%55\% gold.
4. The weight of the gold in the final mixture is the sum of the gold in the original alloy and the pure gold added.
5. The total weight of the final mixture is the sum of the original alloy's weight and the weight of the pure gold added.

STEP 2

1. Determine the amount of gold in the original alloy.
2. Set up an equation based on the percentage of gold in the final mixture.
3. Solve the equation to find the amount of pure gold to be added.
4. Round the answer to two decimal places.

STEP 3

Calculate the amount of gold in the original 4-ounce alloy.
Amount of gold in original alloy=0.20×4 \text{Amount of gold in original alloy} = 0.20 \times 4

STEP 4

Perform the multiplication to find the amount of gold.
Amount of gold in original alloy=0.80 ounces \text{Amount of gold in original alloy} = 0.80 \text{ ounces}

STEP 5

Let xx be the amount of pure gold to be added. Write an equation based on the percentage of gold in the final mixture.
0.80+x4+x=0.55 \frac{0.80 + x}{4 + x} = 0.55

STEP 6

Multiply both sides of the equation by (4+x)(4 + x) to clear the denominator.
0.80+x=0.55(4+x) 0.80 + x = 0.55(4 + x)

STEP 7

Distribute 0.550.55 on the right side of the equation.
0.80+x=0.55×4+0.55x 0.80 + x = 0.55 \times 4 + 0.55x

STEP 8

Perform the multiplication on the right side.
0.80+x=2.20+0.55x 0.80 + x = 2.20 + 0.55x

STEP 9

Subtract 0.55x0.55x from both sides to get all terms involving xx on one side.
0.80+x0.55x=2.20 0.80 + x - 0.55x = 2.20

STEP 10

Combine like terms.
0.80+0.45x=2.20 0.80 + 0.45x = 2.20

STEP 11

Subtract 0.800.80 from both sides to isolate the term with xx.
0.45x=2.200.80 0.45x = 2.20 - 0.80

STEP 12

Perform the subtraction on the right side.
0.45x=1.40 0.45x = 1.40

STEP 13

Divide both sides by 0.450.45 to solve for xx.
x=1.400.45 x = \frac{1.40}{0.45}

STEP 14

Perform the division to find the value of xx.
x3.11 x \approx 3.11

STEP 15

Round the answer to two decimal places.
x3.11 ounces x \approx 3.11 \text{ ounces}
The amount of pure gold that should be added to the 4-ounce alloy to make it 55%55\% gold is approximately 3.113.11 ounces.

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