Math / Geometry

Questionht of each parallelogram. $\begin{array}{l} b=\frac{23 \mathrm{~cm}}{15 \mathrm{~cm}} \\ \mathrm{~h}=\frac{1}{2} \end{array}$ 2. $b=$ $\qquad$ h = $\qquad$
Area of parallelogram $\begin{array}{l} = \\ = \end{array}$ $\qquad$ 4. 5.
Area $=$ $\qquad$ Area $=$ $\qquad$ $=$ $=$

Studdy Solution

STEP 1

What is this asking? We need to find the area of a bunch of parallelograms, given their bases and heights! Watch out! Don't mix up the base and height, and make sure to use the correct units!

STEP 2

1. Parallelogram 1
2. Parallelogram 2
3. Parallelogram 4
4. Parallelogram 5

STEP 3

Alright, for the first parallelogram, we're given that the base is $b = 8 \text{ cm}$ and the height is $h = 12 \text{ cm}$ .
The formula for the area of a parallelogram is base times height!

STEP 4

So, let's calculate the area: $\text{Area} = b \cdot h = 8 \text{ cm} \cdot 12 \text{ cm} = 96 \text{ cm}^2$ Remember, centimeters times centimeters gives us square centimeters!

STEP 5

For parallelogram number two, the base is $b = 23 \text{ cm}$ and the height is $h = 15 \text{ cm}$ .
We'll use the same formula as before: area equals base times height!

STEP 6

Let's multiply: $\text{Area} = b \cdot h = 23 \text{ cm} \cdot 15 \text{ cm} = 345 \text{ cm}^2$ Boom! $345 \text{ cm}^2$ – that's our area!

STEP 7

Now, for parallelogram four, we have a base of $b = 14 \text{ cm}$ and a height of $h = 13 \text{ cm}$ .
We're getting really good at this area formula now!

STEP 8

Calculate the area: $\text{Area} = b \cdot h = 14 \text{ cm} \cdot 13 \text{ cm} = 182 \text{ cm}^2$ Another one down!

STEP 9

Last but not least, parallelogram five has a base of $b = 3 \text{ m}$ and a height of $h = 10 \text{ m}$ .
Notice that the units are in meters this time!

STEP 10

Let's find the area: $\text{Area} = b \cdot h = 3 \text{ m} \cdot 10 \text{ m} = 30 \text{ m}^2$ And that's $30$ square meters!

STEP 11

Parallelogram 1: $96 \text{ cm}^2$ Parallelogram 2: $345 \text{ cm}^2$ Parallelogram 4: $182 \text{ cm}^2$ Parallelogram 5: $30 \text{ m}^2$

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Questionht of each parallelogram. $\begin{array}{l} b=\frac{23 \mathrm{~cm}}{15 \mathrm{~cm}} \\ \mathrm{~h}=\frac{1}{2} \end{array}$ 2. $b=$ $\qquad$ h = $\qquad$
Area of parallelogram $\begin{array}{l} = \\ = \end{array}$ $\qquad$ 4. 5.
Area $=$ $\qquad$ Area $=$ $\qquad$ $=$ $=$

Studdy Solution

STEP 1

What is this asking? We need to find the area of a bunch of parallelograms, given their bases and heights! Watch out! Don't mix up the base and height, and make sure to use the correct units!

STEP 2

1. Parallelogram 1
2. Parallelogram 2
3. Parallelogram 4
4. Parallelogram 5

STEP 3

Alright, for the first parallelogram, we're given that the base is $b = 8 \text{ cm}$ and the height is $h = 12 \text{ cm}$ .
The formula for the area of a parallelogram is base times height!

STEP 4

So, let's calculate the area: $\text{Area} = b \cdot h = 8 \text{ cm} \cdot 12 \text{ cm} = 96 \text{ cm}^2$ Remember, centimeters times centimeters gives us square centimeters!

STEP 5

For parallelogram number two, the base is $b = 23 \text{ cm}$ and the height is $h = 15 \text{ cm}$ .
We'll use the same formula as before: area equals base times height!

STEP 6

Let's multiply: $\text{Area} = b \cdot h = 23 \text{ cm} \cdot 15 \text{ cm} = 345 \text{ cm}^2$ Boom! $345 \text{ cm}^2$ – that's our area!

STEP 7

Now, for parallelogram four, we have a base of $b = 14 \text{ cm}$ and a height of $h = 13 \text{ cm}$ .
We're getting really good at this area formula now!

STEP 8

Calculate the area: $\text{Area} = b \cdot h = 14 \text{ cm} \cdot 13 \text{ cm} = 182 \text{ cm}^2$ Another one down!

STEP 9

Last but not least, parallelogram five has a base of $b = 3 \text{ m}$ and a height of $h = 10 \text{ m}$ .
Notice that the units are in meters this time!

STEP 10

Let's find the area: $\text{Area} = b \cdot h = 3 \text{ m} \cdot 10 \text{ m} = 30 \text{ m}^2$ And that's $30$ square meters!

STEP 11

Parallelogram 1: $96 \text{ cm}^2$ Parallelogram 2: $345 \text{ cm}^2$ Parallelogram 4: $182 \text{ cm}^2$ Parallelogram 5: $30 \text{ m}^2$

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Studdy Solution

STEP 1

What is this asking? We need to find the area of a bunch of parallelograms, given their bases and heights! Watch out! Don't mix up the base and height, and make sure to use the correct units!

STEP 2

1. Parallelogram 12. Parallelogram 23. Parallelogram 44. Parallelogram 5

STEP 3

Alright, for the *first* parallelogram, we're given that the **base** is b=8 cmb = 8 \text{ cm}b=8 cm and the **height** is h=12 cmh = 12 \text{ cm}h=12 cm.The formula for the area of a parallelogram is *base* times *height*!

STEP 4

So, let's **calculate** the area: Area=b⋅h=8 cm⋅12 cm=96 cm2 \text{Area} = b \cdot h = 8 \text{ cm} \cdot 12 \text{ cm} = 96 \text{ cm}^2 Area=b⋅h=8 cm⋅12 cm=96 cm2 Remember, centimeters times centimeters gives us **square centimeters**!

STEP 5

For parallelogram number *two*, the **base** is b=23 cmb = 23 \text{ cm}b=23 cm and the **height** is h=15 cmh = 15 \text{ cm}h=15 cm.We'll use the *same formula* as before: area equals base times height!

STEP 6

Let's **multiply**: Area=b⋅h=23 cm⋅15 cm=345 cm2 \text{Area} = b \cdot h = 23 \text{ cm} \cdot 15 \text{ cm} = 345 \text{ cm}^2 Area=b⋅h=23 cm⋅15 cm=345 cm2 Boom! 345 cm2345 \text{ cm}^2345 cm2 – that's our **area**!

STEP 7

Now, for parallelogram *four*, we have a **base** of b=14 cmb = 14 \text{ cm}b=14 cm and a **height** of h=13 cmh = 13 \text{ cm}h=13 cm.We're getting really good at this area formula now!

STEP 8

**Calculate** the area: Area=b⋅h=14 cm⋅13 cm=182 cm2 \text{Area} = b \cdot h = 14 \text{ cm} \cdot 13 \text{ cm} = 182 \text{ cm}^2 Area=b⋅h=14 cm⋅13 cm=182 cm2 Another one down!

STEP 9

Last but not least, parallelogram *five* has a **base** of b=3 mb = 3 \text{ m}b=3 m and a **height** of h=10 mh = 10 \text{ m}h=10 m.Notice that the units are in **meters** this time!

STEP 10

Let's **find** the area: Area=b⋅h=3 m⋅10 m=30 m2 \text{Area} = b \cdot h = 3 \text{ m} \cdot 10 \text{ m} = 30 \text{ m}^2 Area=b⋅h=3 m⋅10 m=30 m2 And that's 303030 **square meters**!

STEP 11

Parallelogram 1: 96 cm296 \text{ cm}^296 cm2 Parallelogram 2: 345 cm2345 \text{ cm}^2345 cm2 Parallelogram 4: 182 cm2182 \text{ cm}^2182 cm2 Parallelogram 5: 30 m230 \text{ m}^230 m2

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1. Parallelogram 1
2. Parallelogram 2
3. Parallelogram 4
4. Parallelogram 5

Alright, for the first parallelogram, we're given that the base is $b = 8 \text{ cm}$ and the height is $h = 12 \text{ cm}$ .
The formula for the area of a parallelogram is base times height!

So, let's calculate the area: $\text{Area} = b \cdot h = 8 \text{ cm} \cdot 12 \text{ cm} = 96 \text{ cm}^2$ Remember, centimeters times centimeters gives us square centimeters!

For parallelogram number two, the base is $b = 23 \text{ cm}$ and the height is $h = 15 \text{ cm}$ .
We'll use the same formula as before: area equals base times height!

Let's multiply: $\text{Area} = b \cdot h = 23 \text{ cm} \cdot 15 \text{ cm} = 345 \text{ cm}^2$ Boom! $345 \text{ cm}^2$ – that's our area!

Now, for parallelogram four, we have a base of $b = 14 \text{ cm}$ and a height of $h = 13 \text{ cm}$ .
We're getting really good at this area formula now!

Calculate the area: $\text{Area} = b \cdot h = 14 \text{ cm} \cdot 13 \text{ cm} = 182 \text{ cm}^2$ Another one down!

Last but not least, parallelogram five has a base of $b = 3 \text{ m}$ and a height of $h = 10 \text{ m}$ .
Notice that the units are in meters this time!

Let's find the area: $\text{Area} = b \cdot h = 3 \text{ m} \cdot 10 \text{ m} = 30 \text{ m}^2$ And that's $30$ square meters!

Parallelogram 1: $96 \text{ cm}^2$ Parallelogram 2: $345 \text{ cm}^2$ Parallelogram 4: $182 \text{ cm}^2$ Parallelogram 5: $30 \text{ m}^2$