Math

QuestionHow does the equilibrium system adjust when H2 S\mathrm{H}_{2} \mathrm{~S} gas is removed? A, B, C, or D?

Studdy Solution

STEP 1

Assumptions1. The system was initially at equilibrium. . The H \mathrm{H}_{} \mathrm{~} gas is being removed from the system.
3. The system will adjust to reestablish equilibrium according to Le Chatelier's Principle.

STEP 2

Le Chatelier's Principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change. In this case, the removal of H2 \mathrm{H}_{2} \mathrm{~} gas from the system disturbs the equilibrium.

STEP 3

To counteract the removal of H2 \mathrm{H}_{2} \mathrm{~} gas, the system will shift in the direction that produces more H2 \mathrm{H}_{2} \mathrm{~} gas to reestablish equilibrium. This means the reaction will shift to the right (towards the products).

STEP 4

As the reaction shifts to the right, more NH4HS\mathrm{NH}_{4} \mathrm{HS} will be consumed to produce more NH3\mathrm{NH}_{3} and H2 \mathrm{H}_{2} \mathrm{~}. This means the concentration of NH3\mathrm{NH}_{3} will increase.
The correct answer is C. The reaction shifts to the right (products) and the concentration of NH3\mathrm{NH}_{3} increases.

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