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Math

Math Snap

PROBLEM

Identify the restrictions on the domain of f(x)=x3x+5f(x)=\frac{x-3}{x+5}
x5x \neq 5
x5x \neq-5
x=3x=3
x3x \neq-3

STEP 1

What is this asking?
We need to find which values of xx would cause trouble for the function f(x)f(x), specifically making the denominator zero.
Watch out!
Don't mix up the numerator and denominator; we only care about the denominator here!
Also, be careful with the signs.

STEP 2

1. Examine the Denominator
2. Find the Restricted Value
3. State the Domain

STEP 3

Alright, so we've got this cool function, f(x)=x3x+5f(x) = \frac{x - 3}{x + 5}, and we're on the lookout for any domain restrictions.
What could possibly go wrong with this function?
Well, the only thing that could cause a problem is if we divide by zero.

STEP 4

Remember, dividing by zero is a big no-no in math!
It's like trying to divide a pizza into zero slices – it just doesn't make sense!
So, we need to make sure that the denominator of our function, x+5x + 5, is never equal to zero.

STEP 5

Let's set up an equation to find the value of xx that would make the denominator zero:
x+5=0x + 5 = 0

STEP 6

To solve for xx, we need to get xx by itself.
We can do this by adding 5-5 to both sides of the equation.
Remember, what we do to one side, we must do to the other to keep things balanced!
x+5+(5)=0+(5)x + 5 + (-5) = 0 + (-5) x+0=5x + 0 = -5x=5x = -5

STEP 7

So, we found that when x=5x = -5, the denominator becomes 5+5=0 -5 + 5 = 0.
This is exactly what we're trying to avoid!

STEP 8

The domain of a function is all the possible values that xx can take.
Since we found that xx can be any value except 5-5, we can write the domain as x5x \neq -5.
This means xx can be any other number, big or small, positive or negative, but it just can't be 5-5.

SOLUTION

The restriction on the domain of f(x)f(x) is x5x \neq -5.

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