PROBLEM
If
∫abf(x)dx=∫−210f(x)dx+∫1015f(x)dx−∫−25f(x)dx what are the bounds of integration for the first integral?
a= and
b=
STEP 1
1. The problem involves properties of definite integrals.
2. We need to simplify and combine integrals to find the bounds a and b.
STEP 2
1. Simplify the given equation by combining integrals.
2. Identify the bounds a and b.
STEP 3
Start by simplifying the right-hand side of the equation. We have:
∫abf(x)dx=∫−210f(x)dx+∫1015f(x)dx−∫−25f(x)dx Combine the integrals on the right-hand side. Notice that:
∫−210f(x)dx−∫−25f(x)dx=∫510f(x)dx So the equation becomes:
∫abf(x)dx=∫510f(x)dx+∫1015f(x)dx
STEP 4
Now, combine the two integrals on the right-hand side:
∫abf(x)dx=∫515f(x)dx
SOLUTION
From the equation ∫abf(x)dx=∫515f(x)dx, we can directly identify the bounds:
a=5 b=15 The bounds of integration for the first integral are:
a=5 b=15
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