Math  /  Calculus

QuestionIf CFdr=C(x5y3)dx+(x3y)dy\int_{C} \vec{F} \cdot d \vec{r}=\int_{C}\left(-x-5 y^{3}\right) d x+\left(x^{3} y\right) d y, what is F\vec{F} ? F=\vec{F}=

Studdy Solution

STEP 1

1. The line integral is given in terms of its components.
2. The vector field F\vec{F} is expressed in terms of its components F1F_1 and F2F_2.
3. The line integral CFdr\int_{C} \vec{F} \cdot d \vec{r} can be expressed as CF1dx+F2dy\int_{C} F_1 \, dx + F_2 \, dy.

STEP 2

1. Identify the components of the vector field F\vec{F} from the given line integral.
2. Write the vector field F\vec{F} in terms of its components.

STEP 3

The given line integral is:
C(x5y3)dx+(x3y)dy\int_{C}\left(-x-5 y^{3}\right) d x+\left(x^{3} y\right) d y
From this, we can identify the components of the vector field F\vec{F}:
- The component F1F_1 that multiplies dxdx is x5y3-x - 5y^3. - The component F2F_2 that multiplies dydy is x3yx^3 y.

STEP 4

Write the vector field F\vec{F} using the identified components:
F=F1,F2=x5y3,x3y\vec{F} = \langle F_1, F_2 \rangle = \langle -x - 5y^3, x^3 y \rangle
The vector field F\vec{F} is:
x5y3,x3y\boxed{\langle -x - 5y^3, x^3 y \rangle}

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