Math

QuestionFind the inverse of f(x)=3x5+3f(x)=\frac{3 x}{5}+3. Which option is correct? A. f1(x)=3(x+3)5f^{-1}(x)=\frac{3(x+3)}{5} B. f1(x)=5(x3)3f^{-1}(x)=\frac{5(x-3)}{3} C. f1(x)=5(x3)3f^{-1}(x)=\frac{5(x-3)}{3} D. f1(x)=3(x3)5f^{-1}(x)=\frac{3(x-3)}{5}

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=3x5+3f(x)=\frac{3x}{5}+3 . We need to find the inverse of the function f(x)f(x)

STEP 2

The inverse of a function f(x)f(x) is denoted as f1(x)f^{-1}(x). To find the inverse of a function, we switch the roles of xx and yy and then solve for yy.
So, we start by writing f(x)f(x) as yyy=x5+y = \frac{x}{5} +

STEP 3

Now, we switch the roles of xx and yyx=3y5+3x = \frac{3y}{5} +3

STEP 4

We solve this equation for yy to find the inverse function. First, subtract3 from both sidesx3=3yx -3 = \frac{3y}{}

STEP 5

Then, multiply both sides by 53\frac{5}{3} to isolate yyy=5(x3)3y = \frac{5(x -3)}{3}

STEP 6

So, the inverse of the function f(x)f(x) is f1(x)=5(x3)3f^{-1}(x) = \frac{5(x -3)}{3}. Comparing this with the given options, we see that the correct answer is option B.
The inverse of the function f(x)=3x5+3f(x)=\frac{3x}{5}+3 is f1(x)=5(x3)3f^{-1}(x)=\frac{5(x-3)}{3}.

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