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PROBLEM

Find (a) f(1)f(-1), (b) f(0)f(0), and (c) f(4)f(4) for the piecewise function f(x)f(x) defined as:
$$ f(x)=\left\{\begin{array}{ll} x^{2} & \text { if } x<0 \\ 0 & \text { if } x=0 \\ 3 x+3 & \text { if } x>0 \end{array}\right.
$$

STEP 1

Assumptions1. The function f(x)f(x) is defined as a piecewise function with three different expressions for different ranges of xx.
. We need to find the values of f(x)f(x) for x=1x=-1, x=0x=0, and x=4x=4.

STEP 2

We start by finding f(1)f(-1). Since 1-1 is less than 00, we use the expression x2x^{2}.
f(1)=(1)2f(-1) = (-1)^{2}

STEP 3

Calculate the value of f(1)f(-1).
f(1)=(1)2=1f(-1) = (-1)^{2} =1

STEP 4

Next, we find f(0)f(0). Since 00 is equal to 00, we use the expression 00.
f(0)=0f(0) =0

STEP 5

Calculate the value of f(0)f(0).
f(0)=0f(0) =0

STEP 6

Finally, we find f(4)f(4). Since 44 is greater than 00, we use the expression 3x+33x+3.
f(4)=3(4)+3f(4) =3(4) +3

SOLUTION

Calculate the value of f(4)f(4).
f(4)=3(4)+3=15f(4) =3(4) +3 =15So, f(1)=1f(-1) =1, f(0)=0f(0) =0, and f(4)=15f(4) =15.

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