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Math

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PROBLEM

Find ACA C if line yy bisects ACA C, where AB=45xA B=4-5 x and BC=2x+25B C=2 x+25. Solve: 45x=2x+254-5 x=2 x+25

STEP 1

Assumptions1. Line yy bisects ACAC, which means AB=BCAB = BC.
. The length of ABAB is given by 45x4-5x.
3. The length of BCBC is given by x+25x+25.

STEP 2

Since AB=BCAB = BC, we can set the expressions for ABAB and BCBC equal to each other and solve for xx.
45x=2x+254-5x =2x+25

STEP 3

To isolate xx, we can start by adding 5x5x to both sides of the equation to get rid of the negative 5x5x on the left side.
=7x+25 =7x +25

STEP 4

Next, subtract 2525 from both sides to isolate 7x7x on one side of the equation.
21=7x-21 =7x

STEP 5

Finally, divide both sides by 77 to solve for xx.
x=3x = -3

STEP 6

Now that we have the value of xx, we can substitute it into the expressions for ABAB and BCBC to find the lengths of these segments.
For ABAB, we haveAB=45(3)AB =4 -5(-3)

STEP 7

Calculate the length of ABAB.
AB=4+15=19AB =4 +15 =19

STEP 8

For BCBC, we haveBC=2(3)+25BC =2(-3) +25

STEP 9

Calculate the length of BCBC.
BC=6+25=19BC = -6 +25 =19

STEP 10

Since AB=BCAB = BC, and line yy bisects ACAC, the length of ACAC is simply 2×AB2 \times AB or 2×BC2 \times BC.
AC=2×ABAC =2 \times AB

STEP 11

Substitute the value of ABAB into the equation to find ACAC.
AC=×19AC = \times19

SOLUTION

Calculate the length of ACAC.
AC=2×19=38AC =2 \times19 =38So, the length of ACAC is 3838.

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