PROBLEM
If ∣4x−4∣=112, what is the positive value of x−1 ?
STEP 1
1. The equation involves an absolute value, which can result in two cases.
2. We need to solve for x and then find the positive value of x−1.
STEP 2
1. Set up the two cases for the absolute value equation.
2. Solve each case for x.
3. Determine the positive value of x−1.
STEP 3
The absolute value equation ∣4x−4∣=112 can be split into two separate equations:
Case 1: 4x−4=112
Case 2: 4x−4=−112
STEP 4
Solve Case 1: 4x−4=112
Add 4 to both sides:
4x−4+4=112+4 4x=116 Divide by 4:
x=4116 x=29
STEP 5
Solve Case 2: 4x−4=−112
Add 4 to both sides:
4x−4+4=−112+4 4x=−108 Divide by 4:
x=4−108 x=−27
SOLUTION
We need the positive value of x−1.
For x=29:
x−1=29−1 x−1=28 For x=−27:
x−1=−27−1 x−1=−28 The positive value of x−1 is:
28
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