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Math

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PROBLEM

If P16,000 earns P480 in 9 months, what is
the annual rate of interest?
3%
2%
1%
4%

STEP 1

1. The principal amount is P16,000.
2. The interest earned is P480.
3. The time period is 9 months.
4. We need to find the annual rate of interest.
5. The interest is simple interest.

STEP 2

1. Understand the formula for simple interest.
2. Convert the time period to years.
3. Substitute the known values into the simple interest formula.
4. Solve for the annual rate of interest.

STEP 3

Understand the formula for simple interest. The formula is:
Simple Interest (SI)=P×R×T100 \text{Simple Interest (SI)} = \frac{P \times R \times T}{100} Where:
- P P is the principal amount.
- R R is the rate of interest per annum.
- T T is the time period in years.

STEP 4

Convert the time period to years. Since the time given is 9 months, convert it to years:
T=912=34 years T = \frac{9}{12} = \frac{3}{4} \text{ years}

STEP 5

Substitute the known values into the simple interest formula. We know:
- SI=480 \text{SI} = 480
- P=16,000 P = 16,000
- T=34 T = \frac{3}{4}
Substitute these into the formula:
480=16,000×R×34100 480 = \frac{16,000 \times R \times \frac{3}{4}}{100}

SOLUTION

Solve for the annual rate of interest R R .
First, simplify the equation:
480=16,000×R×0.75100 480 = \frac{16,000 \times R \times 0.75}{100} 480=12,000R100 480 = \frac{12,000R}{100} 480=120R 480 = 120R Now, solve for R R :
R=480120 R = \frac{480}{120} R=4 R = 4 The annual rate of interest is:
4% \boxed{4\%}

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