Solve a problem of your own!
Download the Studdy App!

Math

Math Snap

PROBLEM

If possible, find A+B,AB,3AA+B, A-B, 3 A, and 3A4B3 A-4 B. (If not possible, enter IMPOSSIBLE in any cell of the matrix.)
$$A=\left[\begin{array}{rrr} 7 & 0 & 3 \\ -4 & -2 & 0 \end{array}\right], \quad B=\left[\begin{array}{ll}
9 & -1 \\
1 & -4
\end{array}\right]$$ (a) A+BA+B
(b) ABA-B
(c) 3A3 A
(d) 3A4B3 A-4 B

STEP 1

1. Matrix addition and subtraction require matrices of the same dimensions.
2. Scalar multiplication can be performed on any matrix.
3. The given matrices A A and B B have dimensions 2×3 2 \times 3 and 2×2 2 \times 2 , respectively.

STEP 2

1. Determine if A+B A + B is possible.
2. Determine if AB A - B is possible.
3. Calculate 3A 3A .
4. Determine if 3A4B 3A - 4B is possible.

STEP 3

To add matrices A A and B B , they must have the same dimensions. Matrix A A is 2×3 2 \times 3 and matrix B B is 2×2 2 \times 2 . Since they do not have the same dimensions, A+B A + B is not possible.
Result for A+B A + B : IMPOSSIBLE

STEP 4

To subtract matrices A A and B B , they must have the same dimensions. Matrix A A is 2×3 2 \times 3 and matrix B B is 2×2 2 \times 2 . Since they do not have the same dimensions, AB A - B is not possible.
Result for AB A - B : IMPOSSIBLE

STEP 5

To calculate 3A 3A , multiply each element of matrix A A by 3:
\[
3A = 3 \times \begin{bmatrix} 7 & 0 & 3 \\ -4 & -2 & 0 \end{bmatrix}
= \begin{bmatrix} 3 \times 7 & 3 \times 0 & 3 \times 3 \\ 3 \times (-4) & 3 \times (-2) & 3 \times 0 \end{bmatrix}
= \begin{bmatrix} 21 & 0 & 9 \\ -12 & -6 & 0 \end{bmatrix}$$

SOLUTION

To calculate 3A4B 3A - 4B , both matrices must have the same dimensions. Since A A is 2×3 2 \times 3 and B B is 2×2 2 \times 2 , they do not have the same dimensions, and 3A4B 3A - 4B is not possible.
Result for 3A4B 3A - 4B : IMPOSSIBLE
The results are:
(a) A+B A + B : IMPOSSIBLE
(b) AB A - B : IMPOSSIBLE
(c) 3A 3A :
[21091260]\begin{bmatrix} 21 & 0 & 9 \\ -12 & -6 & 0 \end{bmatrix} (d) 3A4B 3A - 4B : IMPOSSIBLE

Was this helpful?
banner

Start understanding anything

Get started now for free.

OverviewParentsContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord