Math

Question Find sec(x)\sec(-x) if sec(x)=2\sec(x)=2.

Studdy Solution

STEP 1

Assumptions
1. sec(x)=1cos(x)\sec(x) = \frac{1}{\cos(x)}
2. sec(x)=1cos(x)\sec(-x) = \frac{1}{\cos(-x)}
3. cos(x)=cos(x)\cos(-x) = \cos(x) (cosine is an even function)
4. Given that sec(x)=2\sec(x) = 2, we need to find sec(x)\sec(-x)

STEP 2

Since sec(x)=2\sec(x) = 2, we can write it as:
sec(x)=1cos(x)=2\sec(x) = \frac{1}{\cos(x)} = 2

STEP 3

To find sec(x)\sec(-x), we use the property of the cosine function being even, which means cos(x)=cos(x)\cos(x) = \cos(-x).

STEP 4

Using the definition of secant in terms of cosine for sec(x)\sec(-x):
sec(x)=1cos(x)\sec(-x) = \frac{1}{\cos(-x)}

STEP 5

Substitute cos(x)\cos(-x) with cos(x)\cos(x) due to the even property of cosine:
sec(x)=1cos(x)\sec(-x) = \frac{1}{\cos(x)}

STEP 6

Since we know sec(x)=2\sec(x) = 2, and sec(x)=1cos(x)\sec(x) = \frac{1}{\cos(x)}, we can substitute 1cos(x)\frac{1}{\cos(x)} with 2:
sec(x)=2\sec(-x) = 2
Thus, sec(x)=2\sec(-x) = 2.

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