Math

QuestionEvaluate the piecewise function f(x)={3x+5 if x<04x+7 if x0f(x)=\left\{\begin{array}{lll}3 x+5 & \text { if } & x<0 \\ 4 x+7 & \text { if } & x \geq 0\end{array}\right. for f(2)f(-2), f(0)f(0), and f(3)f(3).

Studdy Solution

STEP 1

Assumptions1. The function f(x)f(x) is defined as a piecewise function with two parts 3x+53x+5 if x<0x<0, and 4x+74x+7 if x0x \geq0.

STEP 2

We need to evaluate the function f(x)f(x) at three different values 2-2, 00, and $$.
a. To find f(2)f(-2), we need to determine which part of the piecewise function to use. Since 2-2 is less than 00, we use the first part of the function x+5x+5.
f(2)=(2)+5f(-2) =(-2) +5

STEP 3

Now, calculate the value of f(2)f(-2).
f(2)=3(2)+5=6+5=1f(-2) =3(-2) +5 = -6 +5 = -1

STEP 4

b. To find f(0)f(0), we need to determine which part of the piecewise function to use. Since 00 is equal to 00, we use the second part of the function 4x+74x+7.
f(0)=4(0)+7f(0) =4(0) +7

STEP 5

Now, calculate the value of f(0)f(0).
f(0)=4(0)+7=0+7=7f(0) =4(0) +7 =0 +7 =7

STEP 6

c. To find f(3)f(3), we need to determine which part of the piecewise function to use. Since 33 is greater than 00, we use the second part of the function 4x+4x+.
f(3)=4(3)+f(3) =4(3) +

STEP 7

Now, calculate the value of f(3)f(3).
f(3)=4(3)+7=12+7=19f(3) =4(3) +7 =12 +7 =19So, f(2)=1f(-2) = -1, f(0)=7f(0) =7, and f(3)=19f(3) =19.

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