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Math

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PROBLEM

Simplify the expressions and find excluded values: 7. 3x9x26x+9\frac{3 x-9}{x^{2}-6 x+9}, 8. 4x8x24x+4\frac{4 x-8}{x^{2}-4 x+4}.

STEP 1

Assumptions1. We are given two rational expressions 3x9x6x+9\frac{3 x-9}{x^{}-6 x+9} and 4x8x4x+4\frac{4 x-8}{x^{}-4 x+4}.
. We need to simplify these expressions and find the numbers that must be excluded from the domain.

STEP 2

Let's start with the first expression. We can simplify the numerator and the denominator by factoring.
x9x26x+9=(x)(x)2\frac{ x-9}{x^{2}-6 x+9} = \frac{(x-)}{(x-)^2}

STEP 3

Now, we can simplify the expression by cancelling out the common factor (x3)(x-3) from the numerator and the denominator.
3(x3)(x3)2=3x3\frac{3(x-3)}{(x-3)^2} = \frac{3}{x-3}

STEP 4

The denominator of a fraction cannot be zero, so we need to find the values of xx that make the denominator zero.x3=0x-3 =0

STEP 5

olving the equation x3=0x-3 =0 gives us the value of xx that must be excluded from the domain.
x=3x =3

STEP 6

Now, let's move on to the second expression. We can simplify the numerator and the denominator by factoring.
4x8x24x+4=4(x2)(x2)2\frac{4 x-8}{x^{2}-4 x+4} = \frac{4(x-2)}{(x-2)^2}

STEP 7

Now, we can simplify the expression by cancelling out the common factor (x2)(x-2) from the numerator and the denominator.
4(x2)(x2)2=4x2\frac{4(x-2)}{(x-2)^2} = \frac{4}{x-2}

STEP 8

The denominator of a fraction cannot be zero, so we need to find the values of xx that make the denominator zero.x2=0x-2 =0

SOLUTION

olving the equation x2=x-2 = gives us the value of xx that must be excluded from the domain.
x=2x =2So, the simplified expressions are 3x3\frac{3}{x-3} and 4x2\frac{4}{x-2}, and the numbers that must be excluded from the domain are 33 and 22 respectively.

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