QuestionIn a chemistry test, 12 students got As, 18 got Bs, and 19 got Cs. Find the percentage of Bs and Cs to the nearest whole number.

Studdy Solution

STEP 1

Assumptions1. The total number of students is the sum of the students who got As, Bs, and Cs. . The percentage of students who received a certain grade is calculated by dividing the number of students who received that grade by the total number of students, and then multiplying by100.

STEP 2

First, we need to find the total number of students. We can do this by adding the number of students who got As, Bs, and Cs.
$Total\, students = Number\, of\, As + Number\, of\, Bs + Number\, of\, Cs$

STEP 3

Now, plug in the given values for the number of As, Bs, and Cs to calculate the total number of students.
$Total\, students =12 +18 +19$

STEP 4

Calculate the total number of students.
$Total\, students =12 +18 +19 =49$

STEP 5

Now that we have the total number of students, we can find the percentage of students who received Bs. This is calculated by dividing the number of Bs by the total number of students, and then multiplying by100.
$Percentage\, of\, Bs = (Number\, of\, Bs / Total\, students) \\times100$

STEP 6

Plug in the values for the number of Bs and the total number of students to calculate the percentage of Bs.
$Percentage\, of\, Bs = (18 /49) \\times100$

STEP 7

Calculate the percentage of Bs.
$Percentage\, of\, Bs = (18 /49) \\times100 =36.73\%$

STEP 8

Round the percentage of Bs to the ones place.
$Percentage\, of\, Bs =37\%$ The percentage of students who received Bs is37%.

STEP 9

Now we can find the percentage of students who received Cs. This is calculated by dividing the number of Cs by the total number of students, and then multiplying by100.
$Percentage\, of\, Cs = (Number\, of\, Cs / Total\, students) \\times100$

STEP 10

Plug in the values for the number of Cs and the total number of students to calculate the percentage of Cs.
$Percentage\, of\, Cs = (19 /49) \\times100$

STEP 11

Calculate the percentage of Cs.
$Percentage\, of\, Cs = (19 /49) \\times100 =38.78\%$

STEP 12

Round the percentage of Cs to the ones place.
$Percentage\, of\, Cs =39\%$ The percentage of students who received Cs is39%.

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