PROBLEM
In the following problem, divide using long division. State the quotient, q(x), and the remainder, r(x).
x−44x4−3x2+4xx−44x4−3x2+4x=□+x−4□ (Simplify your answers. Do not factor. Use integers or fractions for any numbers in the expressions.)
STEP 1
1. We are performing polynomial long division.
2. The dividend is 4x4−3x2+4x.
3. The divisor is x−4.
4. We need to find both the quotient and the remainder.
STEP 2
1. Set up the long division.
2. Perform the division step-by-step.
3. Identify the quotient and remainder.
STEP 3
Set up the polynomial long division by writing the dividend 4x4−3x2+4x under the division symbol and the divisor x−4 outside.
Divide 4x4 by x to get the first term of the quotient: 4x3
STEP 4
Multiply 4x3 by the divisor x−4 and subtract the result from the dividend.
4x3×(x−4)=4x4−16x3 Subtract:
(4x4−3x2+4x)−(4x4−16x3)=16x3−3x2+4x
STEP 5
Divide 16x3 by x to get the next term of the quotient: 16x2.
Multiply 16x2 by x−4 and subtract the result from the current dividend.
16x2×(x−4)=16x3−64x2 Subtract:
(16x3−3x2+4x)−(16x3−64x2)=61x2+4x
STEP 6
Divide 61x2 by x to get the next term of the quotient: 61x.
Multiply 61x by x−4 and subtract the result from the current dividend.
61x×(x−4)=61x2−244x Subtract:
(61x2+4x)−(61x2−244x)=248x
STEP 7
Divide 248x by x to get the next term of the quotient: 248.
Multiply 248 by x−4 and subtract the result from the current dividend.
248×(x−4)=248x−992 Subtract:
(248x)−(248x−992)=992
SOLUTION
Since there are no more terms to bring down, the remainder is 992.
The quotient is 4x3+16x2+61x+248 and the remainder is 992.
The final result of the division is:
x−44x4−3x2+4x=4x3+16x2+61x+248+x−4992
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