Math

QuestionIn which of the following aqueous solutions would you expect AgBr to have the highest solubility? A) 0.15 M KBr B) 0.10 M LiBr C) pure water D) 0.10MAgNO30.10 \mathrm{M} \mathrm{AgNO}_{3} E) 0.20 M NaBr

Studdy Solution

STEP 1

What is this asking? Which solution lets silver bromide (AgBr) dissolve the most? Watch out! Don't forget that common ions reduce solubility!

STEP 2

1. Identify the common ion effect
2. Compare solubility in different solutions
3. Determine the highest solubility

STEP 3

Alright, let's break it down!
AgBr dissolves in water to form silver ions (Ag+\text{Ag}^+) and bromide ions (Br\text{Br}^-).
When you have other sources of these ions in the solution, it makes it harder for AgBr to dissolve.
This is called the **common ion effect**.
So, if a solution already has Br\text{Br}^- or Ag+\text{Ag}^+, AgBr won't dissolve as much.

STEP 4

Let's look at each option:
- **Option A**: 0.15MKBr0.15 \, \text{M} \, \text{KBr} has Br\text{Br}^- ions.
More Br\text{Br}^- means less AgBr dissolves. - **Option B**: 0.10MLiBr0.10 \, \text{M} \, \text{LiBr} also has Br\text{Br}^- ions.
Again, less solubility for AgBr. - **Option C**: Pure water has no extra ions, so nothing to stop AgBr from dissolving! - **Option D**: 0.10MAgNO30.10 \, \text{M} \, \text{AgNO}_3 has Ag+\text{Ag}^+ ions.
More Ag+\text{Ag}^+ means less AgBr dissolves. - **Option E**: 0.20MNaBr0.20 \, \text{M} \, \text{NaBr} has Br\text{Br}^- ions.
Even more Br\text{Br}^- means even less solubility for AgBr.

STEP 5

Alright, so we know that the more common ions there are, the less AgBr dissolves.
Pure water doesn't have any of these ions, so AgBr can dissolve the most there!

STEP 6

The solution where AgBr has the highest solubility is **C) pure water**.

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