Math  /  Algebra

QuestionInverse?
21. a) y=x3y=\sqrt[3]{x}

Studdy Solution

STEP 1

What is this asking? We're on a mission to find the *inverse* of the function y=x3y = \sqrt[3]{x}, which means we want to find a new function that "undoes" what this one does! Watch out! Don't mix up *inverse* functions with *reciprocal* functions!
The reciprocal of x3\sqrt[3]{x} is 1x3\frac{1}{\sqrt[3]{x}}, which is totally different from the inverse!

STEP 2

1. Swap xx and yy
2. Solve for yy

STEP 3

To start finding the inverse, we **swap** xx and yy in the original equation.
This gives us a new equation: x=y3x = \sqrt[3]{y} Why do we swap?
Think of it like this: the original function takes an input xx and gives you an output yy.
The *inverse* function does the opposite; it takes the output yy (which we now call xx) and gives you back the original input (which we now need to solve for as the new yy).

STEP 4

Now, we want to get yy all by itself.
Since yy is trapped inside a cube root, we can **cube both sides** of the equation to free it! x3=(y3)3x^3 = (\sqrt[3]{y})^3

STEP 5

Cubing a cube root is like hitting the "undo" button!
They cancel each other out, leaving us with: x3=yx^3 = y

STEP 6

We typically write functions with yy on the left side, so let's just **rewrite** this as: y=x3y = x^3 And there you have it!
This is our inverse function!

STEP 7

The inverse of the function y=x3y = \sqrt[3]{x} is y=x3y = x^3.

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