QuestionCheck if 4328 is divisible by 2, 3, 4, 5, 6, 8, 10, and 1. What about 4328 divisible by ??
Studdy Solution
STEP 1
Assumptions1. The number we are testing for divisibility is4328. We are testing for divisibility by the numbers,3,4,5,6,8,10, and1
STEP 2
First, let's test for divisibility by2. A number is divisible by2 if its last digit is0,2,4,6, or8.
STEP 3
Since the last digit of4328 is8,4328 is divisible by2.
STEP 4
Next, let's test for divisibility by3. A number is divisible by3 if the sum of its digits is divisible by3.
STEP 5
Since17 is not divisible by3,4328 is not divisible by3.
STEP 6
Next, let's test for divisibility by4. A number is divisible by4 if the number formed by its last two digits is divisible by4.
STEP 7
Since28 is divisible by4,432 is divisible by4.
STEP 8
Next, let's test for divisibility by5. A number is divisible by5 if its last digit is0 or5.
STEP 9
Since the last digit of4328 is not or5,4328 is not divisible by5.
STEP 10
Next, let's test for divisibility by6. A number is divisible by6 if it is divisible by both2 and3.
STEP 11
Since4328 is divisible by but not by3,4328 is not divisible by6.
STEP 12
Next, let's test for divisibility by8. A number is divisible by8 if the number formed by its last three digits is divisible by8.
STEP 13
Since328 is not divisible by8,4328 is not divisible by8.
STEP 14
Next, let's test for divisibility by10. A number is divisible by10 if its last digit is0.
STEP 15
Since the last digit of4328 is not0,4328 is not divisible by10.
STEP 16
Finally, let's test for divisibility by. A number is always divisible by.
So,4328 is divisible by.
In conclusion,4328 is divisible by2,4, and but not by3,5,6,8, or10.
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