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Math

Math Snap

PROBLEM

Last Sunday, the average temperature was 8% higher than the average temperature two Sundays ago. The average temperature two Sundays ago was TT degrees Celsius.
Which of the following expressions could represent the average temperature last Sunday?
Choose 2 answers:
A. 1.08T1.08T
B. (1+8100)T(1 + \frac{8}{100})T
C. T+0.08T + 0.08
D. 1.8T1.8T
E. T+8T + 8

STEP 1

What is this asking?
If the temperature increased by 8% from a starting temperature TT, what's the new temperature?
Watch out!
Don't mix up adding 8% with multiplying by 8 or adding 0.08!

STEP 2

1. Express the percentage as a decimal.
2. Calculate the increase in temperature.
3. Calculate the final temperature.

STEP 3

We're given an 8% increase.
To work with this mathematically, let's turn this percentage into a decimal!
Remember, "percent" means "per hundred," so 8% is the same as 8100\frac{8}{100}, which equals 0.08.

STEP 4

The problem tells us the temperature two Sundays ago was TT degrees.
The temperature increased by 8% of TT.
Mathematically, this increase is 0.08T0.08 \cdot T.
So the increase is 0.08T0.08T degrees.

STEP 5

To get the final temperature, we take the initial temperature TT and add the increase we just calculated: 0.08T0.08T.
This gives us T+0.08TT + 0.08T.

STEP 6

We can simplify this by factoring out the TT:
T+0.08T=T(1+0.08)=1.08TT + 0.08T = T \cdot (1 + 0.08) = 1.08T So the average temperature last Sunday was 1.08T\bf{1.08T}.

STEP 7

Remember from earlier that we found 8% is the same as 8100\frac{8}{100}?
So, another way to write the final temperature is (1+8100)T\bf{(1 + \frac{8}{100})T}.
It's the same as 1.08T1.08T, just written a little differently!

SOLUTION

The correct answers are A (1.08T1.08T) and B ((1+8100)T(1 + \frac{8}{100})T).

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