Math

QuestionFind limx2+f(x)\lim _{x \rightarrow 2^{+}} f(x) for the piecewise function: f(x)={5x3 if x<2,9 if x=2,4x+3 if x>2}f(x)=\{5x-3 \text{ if } x<2, 9 \text{ if } x=2, 4x+3 \text{ if } x>2\}.

Studdy Solution

STEP 1

Assumptions1. The function f(x)f(x) is a piecewise function defined as - f(x)=5x3f(x) =5x -3 for x<x < - f(x)=9f(x) =9 for x=x = - f(x)=4x+3f(x) =4x +3 for x>x > . We are asked to find the limit of f(x)f(x) as xx approaches from the right, denoted as limx+f(x)\lim{x \rightarrow^{+}} f(x)

STEP 2

The limit as xx approaches2 from the right, limx2+f(x)\lim{x \rightarrow2^{+}} f(x), refers to the value that f(x)f(x) approaches as xx gets infinitely close to2, but is still greater than2.

STEP 3

Since xx is greater than2, we should use the part of the piecewise function defined for x>2x >2, which is f(x)=x+3f(x) =x +3.

STEP 4

Substitute x=2x =2 into the function f(x)=4x+3f(x) =4x +3.
f(2)=4(2)+3f(2) =4(2) +3

STEP 5

Calculate the value of f(2)f(2).
f(2)=4(2)+3=8+3=11f(2) =4(2) +3 =8 +3 =11So, limx2+f(x)=11\lim{x \rightarrow2^{+}} f(x) =11.
The correct answer is (C)11.

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