Math  /  Discrete

QuestionLet the Universal set be the letters a through j:U={a,b,,i,j}j: U=\{a, b, \ldots, i, j\}. Let A={a,c,d,h},B={a,c,e,g}A=\{a, c, d, h\}, B=\{a, c, e, g\}, and C={a,b,d,e}C=\{a, b, d, e\}
List the elements of the set A(BC)A \cap(B \cup C) \square

Studdy Solution

STEP 1

What is this asking? We need to find the letters that are both in set *A* AND in the combined set of *B* OR *C*. Watch out! Don't mix up intersection and union!
Intersection means "AND" (elements in BOTH sets), while union means "OR" (elements in EITHER set).

STEP 2

1. Find the union of *B* and *C*.
2. Find the intersection of *A* and the result from the previous step.

STEP 3

Let's **start** by finding BCB \cup C, which means all the elements in *B* OR *C* (or both!). *B* has {a,c,e,g}\{a, c, e, g\} and *C* has {a,b,d,e}\{a, b, d, e\}.
Combining these, we get {a,b,c,d,e,g}\{a, b, c, d, e, g\}.
Notice how we only include *a* and *e* once, even though they appear in both sets!

STEP 4

Now, we want to find A(BC)A \cap (B \cup C).
This means we're looking for the letters that are in BOTH *A* AND the set we just found, {a,b,c,d,e,g}\{a, b, c, d, e, g\}.

STEP 5

Set *A* is {a,c,d,h}\{a, c, d, h\}.
Let's compare it to {a,b,c,d,e,g}\{a, b, c, d, e, g\}.
Both sets contain {a,c,d}\{a, c, d\}, so that's our **intersection**!

STEP 6

The elements of the set A(BC)A \cap (B \cup C) are {a,c,d}\{a, c, d\}.

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