QuestionListen
List the correct balanced coefficients for the following reaction :
A)
B)
C)
D)
E)
Studdy Solution
STEP 1
1. The chemical equation given is:
$ \mathrm{HF} + \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \rightarrow \mathrm{CaF}_{2} + \mathrm{H}_{3}\left(\mathrm{PO}_{4}\right)
\]
2. We need to balance the equation by ensuring the same number of each type of atom on both sides of the equation.
STEP 2
1. Identify the number of each type of atom in the reactants and products.
2. Balance the equation by adjusting coefficients.
3. Verify that the equation is balanced.
STEP 3
Identify the number of each type of atom in the reactants and products.
- Reactants:
- : 1 H, 1 F
- : 3 Ca, 2 P, 8 O
- Products:
- : 1 Ca, 2 F
- : 3 H, 1 P, 4 O
STEP 4
Balance the equation by adjusting coefficients.
- Start by balancing the calcium () atoms:
- Reactants have 3 Ca from .
- Products have 1 Ca in .
- Place a coefficient of 3 in front of :
$ \mathrm{HF} + \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \rightarrow 3\mathrm{CaF}_{2} + \mathrm{H}_{3}\left(\mathrm{PO}_{4}\right)
\]
- Balance the fluorine () atoms:
- Products now have 6 F (from 3 ).
- Reactants have 1 F in .
- Place a coefficient of 6 in front of :
$ 6\mathrm{HF} + \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \rightarrow 3\mathrm{CaF}_{2} + \mathrm{H}_{3}\left(\mathrm{PO}_{4}\right)
\]
- Balance the hydrogen () atoms:
- Reactants now have 6 H (from 6 ).
- Products have 3 H in .
- Place a coefficient of 2 in front of :
$ 6\mathrm{HF} + \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \rightarrow 3\mathrm{CaF}_{2} + 2\mathrm{H}_{3}\left(\mathrm{PO}_{4}\right)
\]
- Balance the phosphorus () and oxygen () atoms:
- Reactants have 2 P and 8 O from .
- Products have 2 P and 8 O from 2 .
STEP 5
Verify that the equation is balanced.
- Reactants: 6 H, 6 F, 3 Ca, 2 P, 8 O
- Products: 6 H, 6 F, 3 Ca, 2 P, 8 O
The equation is balanced.
The correct balanced coefficients are:
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