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Math

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PROBLEM

\ln |y| = \ln |x| + c \\
\text{Solve for } y

STEP 1

1. The equation involves natural logarithms.
2. We assume c c is a constant.
3. We are solving for y y in terms of x x and c c .

STEP 2

1. Use properties of logarithms to simplify the equation.
2. Solve for the absolute value of y y .
3. Consider the absolute value to solve for y y .

STEP 3

Use the property of logarithms that states lna+lnb=ln(ab)\ln a + \ln b = \ln(ab). Here, we can rewrite the right side of the equation:
lny=lnx+c\ln |y| = \ln |x| + c Rewriting c c as lnec\ln e^c, we have:
lny=ln(xec)\ln |y| = \ln (|x| \cdot e^c)

STEP 4

Since the natural logarithm function is one-to-one, if lna=lnb\ln a = \ln b, then a=ba = b. Therefore, we equate the arguments of the logarithms:
y=xec|y| = |x| \cdot e^c

SOLUTION

Consider the absolute value to solve for y y . Since y=xec|y| = |x| \cdot e^c, we have two cases for y y :
1. y=xec y = |x| \cdot e^c
2. y=xec y = -|x| \cdot e^c
Thus, the solution for y y is:
y=±xecy = \pm |x| \cdot e^c The solution for y y is:
y=±xecy = \pm |x| \cdot e^c

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