Math  /  Algebra

Questionlog636x=1\log _{6} 36 x=1

Studdy Solution

STEP 1

1. The equation log6(36x)=1\log_{6}(36x) = 1 involves a logarithm with base 6.
2. We will need to use properties of logarithms to solve for xx.

STEP 2

1. Convert the logarithmic equation to an exponential equation.
2. Solve the resulting equation for xx.

STEP 3

Convert the logarithmic equation to an exponential form. Recall that if logb(a)=c\log_b(a) = c, then bc=ab^c = a. Thus, we have:
61=36x6^1 = 36x

STEP 4

Solve the exponential equation for xx. Start by simplifying the equation:
6=36x6 = 36x
Next, divide both sides by 36 to isolate xx:
x=636x = \frac{6}{36}
Simplify the fraction:
x=16x = \frac{1}{6}
The value of xx is:
16\boxed{\frac{1}{6}}

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