Math  /  Algebra

Question1
Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10%10 \% each year. If there were 80 million cars in year 1 of her study, how many more cars were on the road in year 3 compared to year 2 ? 8,000,0008,000,000 8,800,000 88,000,000 96,800,000 Save and Exit Next Submit Mark this and return

Studdy Solution

STEP 1

What is this asking? If the number of cars grows by 10% each year, starting with 80 million, how many *more* cars are there in year 3 than in year 2? Watch out! Don't just calculate the number of cars in year 3.
We need the *difference* between year 3 and year 2!

STEP 2

1. Calculate cars in year 2.
2. Calculate cars in year 3.
3. Find the difference.

STEP 3

Alright, so we **start** with 80 million cars.
After one year, there's a **10% increase**.
That means we multiply by 1+0.10=1.101 + 0.10 = 1.10.
Why? Because multiplying by 1 keeps the original amount, and multiplying by 0.10 gives us the 10% increase.
Adding them together gives us the **new total**.

STEP 4

So, the number of cars in year 2 is 80,000,0001.10=88,000,00080,000,000 \cdot 1.10 = 88,000,000.
Boom! **88 million** cars in year 2.

STEP 5

Now, we do the *same thing* again!
We take the number of cars in year 2, which is **88 million**, and multiply by 1.101.10 to find the number in year 3.
Remember, multiplying by 1.101.10 is the same as adding 10% to the current amount.

STEP 6

So, 88,000,0001.10=96,800,00088,000,000 \cdot 1.10 = 96,800,000.
Awesome! **96.8 million** cars in year 3.

STEP 7

The problem asks for how many *more* cars there are in year 3 compared to year 2.
So, we just **subtract** the number of cars in year 2 from the number in year 3.

STEP 8

That's 96,800,00088,000,000=8,800,00096,800,000 - 88,000,000 = 8,800,000.
So, there are **8.8 million** more cars in year 3 than in year 2!

STEP 9

The answer is **8,800,000**.

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