Math

QuestionMarta solves S=2πrh+2πr2S=2 \pi r h+2 \pi r^{2} for hh. What is the correct expression for hh?

Studdy Solution

STEP 1

Assumptions1. The given equation is =πrh+πr= \pi r h+ \pi r^{} . We are solving for hh

STEP 2

First, we need to isolate the term with hh on one side of the equation. To do this, we subtract 2πr22 \pi r^{2} from both sides of the equation.
2πr2=2πrh -2 \pi r^{2} =2 \pi r h

STEP 3

Next, to solve for hh, we need to divide both sides of the equation by 2πr2 \pi r.
2πr22πr=h\frac{ -2 \pi r^{2}}{2 \pi r} = hThis is the solution for hh in terms of $$, $r$, and $\pi$. However, none of the given options match this exact form. We can simplify this expression further.

STEP 4

We can divide the numerator in the fraction on the left side of the equation by 2πr2 \pi r.
h=2πrrh = \frac{}{2 \pi r} - rThis is the simplified form of the equation for hh. Comparing this with the given options, we see that it matches the first option.
So, Marta should get 2πrr=h\frac{}{2 \pi r} - r = h as the result. END

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